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C Program for sum of cos(x) series
We are given with the value of x and n where, x is the angle for cos and n is the number of terms in the cos(x) series.
For Cos(x)
Cos(x) is a trigonometric function which is used to calculate the value of x angle.
Formula
$$\cos (x) = \displaystyle\sum\limits_{k=0}^\infty \frac{(-1)^{k}}{(2k!)}x^{2k}$$
For Cos(x) series
Cos(x) = 1 – (x*2 / 2!) + (x*4 / 4!) – (x*6 / 6!) + (x*8 / 8!)……
Example
Input-: x = 10, n = 3 Output-: 0.984804 Input-: x = 8, n = 2 Output-: 0.990266
Approach used in the below program is as follows −
- Input the value of x and n
- Apply the formula for calculating cos(x) series
- Print the result as the sum of all the series
Algorithm
Start Step 1 Declare and initialize const double PI = 3.142 Step 2 In function double series_sum(double x, int n) Set x = x * (PI / 180.0) Set result = 1 Set s = 1, fact = 1, pow = 1 Loop For i = 1 and i < 5 and i++ Set s = s * -1 Set fact = fact * (2 * i - 1) * (2 * i) Set pow = pow * x * x Set result = result + s * pow / fact End Loop Return result Step 3 In function int main() s Declare and set x = 10 Declare and set n = 3 Print series_sum(x, n) Stop
Example
#include <stdio.h>
const double PI = 3.142;
//will return the sum of cos(x)
double series_sum(double x, int n) {
x = x * (PI / 180.0);
double result = 1;
double s = 1, fact = 1, pow = 1;
for (int i = 1; i < 5; i++) {
s = s * -1;
fact = fact * (2 * i - 1) * (2 * i);
pow = pow * x * x;
result = result + s * pow / fact;
}
return result;
}
//main function
int main() {
float x = 10;
int n = 3;
printf("%lf
", series_sum(x, n));
return 0;
}Output
X=10; n=30.984804 X=13; n=80.974363 X=8; n=2 0.990266
Updated on: 20-Nov-2019
5K+ Views
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