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C program to calculate sum of series using predefined function
Problem
The program to calculate the sum of the following expression
Sum=1-n^2/2!+n^4/4!-n^6/6!+n^8/8!-n^10/10!
User has to enter the value of n at runtime to calculate the sum of the series by using the predefined function power present in math.h library function.
Solution
It is explained below how to calculate sum of series using predefined function.
Algorithm
Refer an algorithm given below to calculate sum of series by using the predefined function.
Step 1 − Read the num value
Step 2 − Initialize fact = 1, sum = 1 and n =5
Step 3 − for i= 1 to n
a. compute fact= fact*i b. if i %2 = 0 c. then if i=2 or i=10 or i=6 d. then sum+= -pow(num,i)/fact e. else sum+=pow(num,i)/fact 4. print sum
Example
Following is the C program to calculate sum of series by using the predefined function −
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main(){
int i,n=5,num;
long int fact=1;
float sum=1;
printf("Enter the n value:");
scanf("%d", &num);
for(i=1;i<=n;i++){
fact=fact*i;
if(i%2==0){
if(i==2|i==10|i==6)
sum+= -pow(num,i)/fact;
else
sum+=pow(num,i)/fact;
}
}
printf("sum is %f", sum);
}Output
When the above program is executed, it produces the following result −
Enter the n value:10 sum is 367.666656
Updated on: 31-Aug-2021
633 Views
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