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C program to find the sum of arithmetic progression series
Problem
Find the sum of an arithmetic progression series, where the user has to enter first number, total number of elements and the common difference.
Solution
Arithmetic Progression (A.P.) is a series of numbers in which the difference of any two consecutive numbers is always the same. Here, total number of elements is mentioned as Tn.
Sum of A.P. Series: Sn = n/2(2a + (n – 1) d) Tn term of A.P. Series: Tn = a + (n – 1) d
Algorithm
Refer an algorithm given below to find the arithmetic progression.
Step 1: Declare variables. Step 2: Initialize sum=0 Step 3: Enter first number of series at runtime. Step 4: Enter total number of series at runtime. Step 5: Enter the common difference at runtime. Step 6: Compute sum by using the formula given below. sum = (num * (2 * a + (num - 1) * diff)) / 2 Step 7: Compute tn by using the formula given below. tn = a + (num - 1) * diff Step 8: For loop i = a; i <= tn; i = i + diff i. if(i != tn) printf("%d + ", i); ii. Else, printf("%d = %d", i, sum); Step 9: Print new line
Program
Following is the C Program to find the sum of arithmetic progression series−
#include <stdio.h> int main() { int a, num, diff, tn, i; int sum = 0; printf(" enter 1st no of series: "); scanf("%d", &a); printf(" enter total no's in series: "); scanf("%d", &num); printf("enter Common Difference: "); scanf("%d", &diff); sum = (num * (2 * a + (num - 1) * diff)) / 2; tn = a + (num - 1) * diff; printf("\n sum of A.P series is : "); for(i = a; i <= tn; i = i + diff){ if(i != tn) printf("%d + ", i); else printf("%d = %d", i, sum); } printf("\n"); return 0; }
Output
When the above program is executed, it produces the following result −
enter 1st no of series: 3 enter total no's in series: 10 enter Common Difference: 5 sum of A.P series is: 3 + 8 + 13 + 18 + 23 + 28 + 33 + 38 + 43 + 48 = 255 enter 1st no of series: 2 enter total no's in series: 15 enter Common Difference: 10 sum of A.P series is: 2 + 12 + 22 + 32 + 42 + 52 + 62 + 72 + 82 + 92 + 102 + 112 + 122 + 132 + 142 = 1080
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