Sunidhi Bansal

Sunidhi Bansal

809 Articles Published

Articles by Sunidhi Bansal

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Program for Fibonacci numbers in PL/SQL

Sunidhi Bansal
Sunidhi Bansal
Updated on 24-Dec-2024 13K+ Views

Given ‘n’ numbers the task is to generate the Fibonacci numbers in PL/SQL starting from 0 to n, where the Fibonacci series of integers is in the form 0, 1, 1, 2, 3, 5, 8, 13, 21, 34 Where integers 0 (1st place) and 1 (2nd place) will have a fixed place after that, the previous two digits will be added to get the integer of the next place as shown below. 0+1=1 (3rd place) 1+1=2 (4th place) 2+1=3 (5th place) and So on. Formula Sequence F(n) ...

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Count set bits in an integer in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Dec-2024 5K+ Views

We are given an integer number let’s say, num and the task is to first calculate the binary digit of a number and then calculate the total set bits of a number. Set bits in a binary number are represented by 1. Whenever we calculate the binary number of an integer value then it is formed as the combination of 0’s and 1’s. So, the digit 1 is known as a set bit in terms of the computer. Example 1 Input − int number = 50 Output − The count ...

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Program for Point of Intersection of Two Lines in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 02-Dec-2024 5K+ Views

Given points A and B corresponding to line AB and points P and Q corresponding to line PQ; the task is to find the point of intersection between these two lines. Note − The points are given in 2D plane on X and Y coordinates. Here A(a1, a2), B(b1, b2) and C(c1, c2), D(d1, d2) are the coordinates which are forming two distinct lines and P(p1, p2) is the point of intersection. (just for a diagrammatic explanation of the point of intersection) How to find the point of intersection − Let’s take the above figure as − Example So ...

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Java program to convert Byte array to IP Address

Sunidhi Bansal
Sunidhi Bansal
Updated on 24-Sep-2024 1K+ Views

In this article, we will learn to convert a byte array into an IP address using the IPAddress class in Java. This program takes a series of bytes, representing an IP address in binary form, and converts them into a standard dot-separated string representation of an IP address. We'll go through the simple steps of declaring a byte array and then converting it into a readable IP address format. What is a Byte Array? A byte comprises 8 bits and a byte array comprises contiguous bytes which store the binary information. In Java, a byte is a primitive datatype that can ...

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Merge Sort Tree in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 05-Nov-2021 788 Views

We are given an integer array, a set of segment start and end pointers and a key value and the problem statement here is to find all the values in the given range which are smaller than or equal to the given key value.Let us understand with exampleInput − arr[] = {7, 8 , 1, 4 , 6 , 8 , 10 }Segment 1: start = 2, end = 4, k = 2Segment 2: start = 1, end = 6, k = 3Output − Count of number which are smaller than or equal to key value in the given range are 2 ...

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Merge Sort using Multithreading in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 05-Nov-2021 4K+ Views

We are given an unsorted integer array. The task is to sort the array using merge sort technique implemented via Multi-threadingMerge SortMerge sort is a sorting technique which is based on divide and conquer technique where we divide the array into equal halves and then combine them in a sorted manner.Algorithm to implement merge sort ischeck if there is one element in the list then return the element.Else, Divide the data recursively into two halves until it can’t be divided further.Finally, merge the smaller lists into new lists in sorted order.Multi-ThreadingIn the operating system, Threads are the lightweight process which ...

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Memorization (1D, 2D and 3D) Dynamic Programming in Java

Sunidhi Bansal
Sunidhi Bansal
Updated on 05-Nov-2021 2K+ Views

Memorization is a technique based on dynamic programming which is used to improve the performance of a recursive algorithm by ensuring that the method does not run for the same set of inputs more than once by keeping a record of the results for the provided inputs(stored in an array).Memorization can be achieved by implementing top down approach of the recursive method.Let us understand this scenario with the help of basic Fibonacci example1-D MemorizationWe will be considering a recursive algorithm with only one non constant parameter (only one parameter changes its value) hence this method is called 1-D memorization. The ...

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Find array using different XORs of elements in groups of size 4 in Java

Sunidhi Bansal
Sunidhi Bansal
Updated on 05-Nov-2021 233 Views

We are given with an integer array of size N(size of multiple 4) and we have to perform Xclusive OR operation on the array such that input[1- 4] resembles utility_arr[1- 4] and the conditions of computing is If arr[1 – 4] = {a1, a2, a3, a4} then q[1 – 4] = {a1 ⊕ a2 ⊕ a3, a1 ⊕ a2 ⊕ a4, a1 ⊕ a3 ⊕ a4, a2 ⊕ a3 ⊕ a4}Let us see various input output scenarios for this -In − int[] input = { 5, 2, 3, 4 };Out − Result after XOR operation 4 3 2 5Explanation −An Exclusive-OR gate's output ...

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Meet in the middle in Java

Sunidhi Bansal
Sunidhi Bansal
Updated on 05-Nov-2021 477 Views

We are provided with an array and a sum value; the problem statement is to calculate the maximum subset sum which does not exceed the given sum value. We cannot apply the brute force approach here because the structure of the given array is not the same as the divide and conquer approach.Let us see various input output scenarios for this -Let us understand with exampleInput − long arr[] = { 21, 1, 2, 45, 9, 8 } long given_Sum = 12Output −The maximum sum subset having sum less than or equal to the given sum-->12Explanation −The array is split into a set ...

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Maximize the total profit of all the persons X in Java

Sunidhi Bansal
Sunidhi Bansal
Updated on 05-Nov-2021 434 Views

We are given 5 Integer variables Num, P1, P2, profit_P1, profit_P2 and the task is to maximize the profit and from all the natural numbers in the range of [1, Num]. The approach here is that if a positive number is divisible by P1 the profit increases by profit_P1 and similarly if if the number in the range is divisible by P2 the profit margin of profit_P2 increases. Also, the profit from a positive integer can be added at most once.Let us understand with example:-Input − int num = 4, P1 = 6, P2 = 2, profit_P1 = 8, profit_P2 = ...

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