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Articles by Ayush Gupta
Page 38 of 44
Program to find N-th term of series 0, 11, 28, 51, 79, 115, 156, 203, ...In C++
In this problem, we are given a number N. Our task is to create a program to find N-th term of series 0, 11, 28, 51, 79, 115, 156, 203, … In C++.Problem Description − To find the Nth terms of the series −0, 11, 28, 51, 79, 115, 156, 203, … N-th term.Let’s take an example to understand the problem,Input − N = 5Output − 79Solution Approach:The general formula for nth term of the series is −Tn = 3*(N*N) + 2*N - 5Program to illustrate the working of our solution,#include using namespace std; int findNTerm(int N) { int nthTerm = ( (3*N*N) + 2*N - 5); return nthTerm; } int main() { int N = 9; cout
Read MoreProgram to find N-th term of series 2, 12, 28, 50, 77, 112, 152, 198, ...in C++
In this problem, we are given a number N. Our task is to create a program to find N-th term of series 2, 12, 28, 50, 77, 112, 152, 198, …in C++.Problem Description − To find the N-th term of the series.2, 12, 28, 50, 77, 112, 152, 198, ...N termsWe will find a general for the series.Let’s take an example to understand the problem, Input − N = 6Output − 112Solution Approach:Here, the series is increasing in parabolic form, so the general term will be a quadratic equation.So, the general formula for the series isTN = 3*(N*N) + N ...
Read MoreProgram to find N-th term of series 1 4 15 24 45 60 92... in C++
In this problem, we are given a number N. Our task is to create a program to find N-th term of series 1 4 15 24 45 60 92... in C++.Problem description − To find the nth term of the series −1, 4, 15, 24, 45, 60, 92, 112 … N termsWe will find the general formula for the series.Let’s take an example to understand the problem, Input − N = 6Output − 60Solution Approach, The general term of the series is based on whether the value of N is even or odd. This type of series is a bit ...
Read MoreProgram to find N-th term of series 2, 4, 3, 4, 15... in C++
In this problem, we are given a number N. Our task is to create a program to find N-th term of series 2, 4, 3, 4, 15… in C++.Problem Description − To find the sum of the given series, 2, 4, 3, 4, 15, 0, 14, 16 .... N termsWe will find the formula for the general term of the series.Let’s take an example to understand the problem, Input − N = 9Output − 9Solution Approach:The increase of the values in the series is linear i.e. no square values are in the series. Also, it’s value depends on other factors ...
Read MoreProgram to find number of solutions in Quadratic Equation in C++
In this problem, we are given a quadratic equation of type ax2 + bx + c, where a, b and c are constants. Our task is to create a program to find number of solutions in Quadratic Equation in C++.Problem Description − Here, we need to find the numbers of solutions for a quadratic equation that can have at max 2 solutions.Let’s take a few examples to understand the problem, Example 1:Input − 3x2 + 7x + 4Output − 2Explanation − the two solutions of the equation are 1 and 4/3.Example 2:Input − x2 - 4x + 4Output − 1Explanation ...
Read MoreProgram to find number of squares in a chessboard in C++
In this problem, we are given the size of a chessboard. Our task is to create a program to find number of squares in a chessboard in C++.Problem Description − To find the number of squares in a chessboard. We will have to calculate all the combinations of the square that are inside the chessboard i.e. we will consider squares of side 1x1, 2x2, 3x3 … nxn.Let’s take an example to understand the problem, Input: n = 4.Output: 30Squares of size 1x1 -> 16 Squares of size 2x2 -> 9 Squares of size 3x3 -> 4 Squares of size 4x4 ...
Read MoreProgram to find Perimeter / Circumference of Square and Rectangle in C++
In this problem, we are given the side of a square (A) and the length and breadth of a rectangle (L and B). Our task is to create a Program to find Perimeter / Circumference of Square and Rectangle in C++.Problem Description:To find the circumference of a square, we need the side of the square (a). For that, we will use the formula for the perimeter of the square which is 4a.To find the circumference of a rectangle, we need the Length (L) and breadth (B) of the rectangle. For that, we will use the formula for the perimeter of ...
Read MoreMaximum product of an increasing subsequence of size 3 in C++
In this tutorial, we will be discussing a program to find maximum product of an increasing subsequence of size 3.For this we will be provided with an array of positive integers. Our task is to find a subsequence of three elements with the maximum product.Example#include using namespace std; //returning maximum product of subsequence long long int maxProduct(int arr[] , int n) { int smaller[n]; smaller[0] = -1 ; setS ; for (int i = 0; i < n ; i++) { auto j = S.insert(arr[i]); auto itc = j.first; ...
Read MoreC++ program to implement Run Length Encoding using Linked Lists
In this tutorial, we will be discussing a program to implement Run Length Encoding using Linked Lists.For this we will be given with a linked list. OUr task is too encode the elements of the Linked List using Run Length Encoding.For example, if the elements of the linked list are “a->a->a->a->a” then in run length encoding they will be replaced by “a → 5”.Example#include using namespace std; //structuring linked list node struct Node { char data; struct Node* next; }; //creating a new node Node* newNode(char data){ Node* temp = new Node; temp->data = data; ...
Read MoreC++ program to find the rate percentage from compound interest of consecutive years
In this tutorial, we will be discussing a program to find the rate percentage from compound interest of the consecutive years.For this, we will be provided with two integers say A and B that are the interests of two consecutive years. Our task is to find the rate of interest for the given values.Finding the relation between the given values and eliminating the principal amount, we get the formula asrate = ((B-A)*100)/AExample#include using namespace std; //calculating the rate of interest float calc_rate(int N1, int N2) { float rate = (N2 - N1) * 100 / float(N1); return ...
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