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Convert a number m to n using minimum number of given operations in C++
In this tutorial, we will be discussing a program to convert a number m to n using minimum number of given operations.
For this we will be provided with two integers m and n. Our task is to convert the integer m to n using the given operations least times.
Allowed operations −
Multiply the given number by 2
Subtract one from the given number
Example
#include <bits/stdc++.h>
using namespace std;
//finding minimum number of operations required
int convert(int m, int n){
if (m == n)
return 0;
if (m > n)
return m - n;
//can't convert in this situation
if (m <= 0 && n > 0)
return -1;
//when n is greater and n is odd
if (n % 2 == 1)
//performing '-1' on m
return 1 + convert(m, n + 1);
//when n is even
else
//performing '*2' on m
return 1 + convert(m, n / 2);
}
int main(){
int m = 5, n = 11;
cout << "Minimum number of operations : " << convert(m, n);
return 0;
}Output
Minimum number of operations : 5
Updated on: 06-Jan-2020
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