Arnab Chakraborty

Arnab Chakraborty

3,768 Articles Published

Articles by Arnab Chakraborty

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C++ code to find array from given array with conditions

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 219 Views

Suppose we have an array A with n elements. There is another hidden array B of size n. The elements can be negative or positive. For each index i in range 1 to n, following operations will be performed −Set A[i] as 0 initiallyThen add B[i] to A[i], subtract B[i+1], then add B[i+2] and so onWe have to find the array B.So, if the input is like A = [6, -4, 8, -2, 3], then the output will be [2, 4, 6, 1, 3]StepsTo solve this, we will follow these steps −for initialize i := 0, when i < size ...

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C++ code to find minimum stones after all operations

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 349 Views

Suppose we have a string S with n characters. The characters will be either '+' or '-'. There is a pile of stones, n times we either took one stone from the pile or added one stone to the pile. The pile was non-empty before each operation of taking one stone from the pile. We have to find the minimal possible number of stones that can be in the pile after making these operations. If we took the stone on i-th operation, S[i] is equal to "-", if added, S[i] is equal to "+".So, if the input is like S ...

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C++ code to check grasshopper can reach target or not

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 367 Views

Suppose we have a string S of size n and another number k. The string contains four types of characters. Consider there are few cells, a grasshopper wants to jump to reach the target. Character '.' means that the corresponding cell is empty, character '#' means that the corresponding cell contains an obstacle and grasshopper can't jump there. 'G' means that the grasshopper starts at this position and, 'T' means that the target cell. The grasshopper is able to jump exactly k cells away from its current position. We have to check whether the grasshopper can jump to the target ...

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C++ code to count colors to paint elements in valid way

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 351 Views

Suppose we have an array A with n elements. We need to paint elements in colors such that −If we consider any color, all elements of this color must be divisible by the minimal element of the same color.The number of used colors should be minimized.We have to find the minimum number of colors to paint all the given numbers in a valid way.So, if the input is like A = [10, 2, 3, 5, 4, 2], then the output will be 3, because paint the first color to the elements A[0] and A[3], paint second color to the elements ...

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C++ code to get minimum sum of cards after discarding

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 226 Views

Suppose we have five numbers in an array T. There are five cards and each card has a number written on them. The ith card has T[i] written on it. We can discard some cards and our goal is to minimize the sum of numbers written on remaining numbers. He is allowed to at most once discard two or three cards with the same number. We won't discard cards if it's impossible to choose two or three cards with the same number. We have to find the minimum sum possible.So, if the input is like T = [7, 3, 7, ...

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C++ code to find a point that satisfies the constraints

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 391 Views

Suppose, we are given two points a = (x1, y1) and b = (x2, y2). The Manhattan distance between two points is dist(a, b) = |x1 - x2| + |y1 - y2|. If the point a's coordinate is (0, 0) and the point b's coordinate is (x, y), we have to find a point c such that dist(a, c) = dist(a, b)/ 2 and dist(b, c) = dist(a, b)/2. If a point like that is not available then, we print -1, -1.So, if the input is like x = 13, y = 7, then the output will be 6, 4.StepsTo ...

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C++ code for calculation of a physics experiment

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 917 Views

Suppose, we are performing a physics experiment. We are given n pairs of values and a threshold value k. Each the first value of the pair is added to a total value and the second value of the pair is also added to another total value. Now, we check if a total value is minimum or the (k - total) value is minimum. We do this for both the totals and then add them and print the output.So, if the input is like n = 4, k = 20, values = {{3, 5}, {4, 3}, {2, 1}, {4, 4}}, then ...

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C++ code to find out which number can be greater

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 556 Views

Suppose, we are given two k-digit numbers m and n. The digits of the numbers are randomly shuffled and then compared. We have to find out which number has a higher probability to be greater.So, if the input is like n = 231, m = 337, k = 3, then the output will be ‘Second’, or the second number has a higher probability to be greater.StepsTo solve this, we will follow these steps −s1 := convert n to string s2 := convert m to string f := 0, s = 0 for initialize i := 0, when i < k, ...

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C++ code to find out if a name is male or female

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 1K+ Views

Suppose, we are given n strings in an array 'input'. The strings are names, we have to find out if they are male or female names. If a name ends with 'a', 'e', 'i', or 'y'; it can be said that it is a female name. we print 'male' or 'female' for each input in the string.So, if the input is like n = 5, input = {"Lily", "Rajib", "Thomas", "Riley", "Chloe"}, then the output will be Female, Male, Male, Female, Female.StepsTo solve this, we will follow these steps −for initialize i := 0, when i < n, update (increase ...

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C++ code to find the number of scans needed to find an object

Arnab Chakraborty
Arnab Chakraborty
Updated on 29-Mar-2022 256 Views

Suppose, we are given a grid of dimensions m x n. An object is placed at cell (ix, iy) and we have to find the object scanning from a starting position (sx, sy). The scanning algorithm scans the ith row and the j-th column of the grid if it is located at cell (i, j) of the grid. If it has found the object, the scanning stops; if not, the scanning pointer moves to cell in position (i + 1, j + 1) and then scans in the same way. This continues until the item is found. Given the positions, ...

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