Suppose we have an array A. We have to replace every element by the greatest element on the right side of this element. And replace the last one by -1. So if A = [5, 17, 40, 6, 3, 8, 2], then it will be [40,40,8,8,8,2,-1]To solve this, we will follow these steps −We will read the array element from right to left.take e := -1for i := n – 1 to 0temp := ee := max between e and array[i]array[i] := tempreturn arrayExampleLet us see the following implementation to get better understanding − Live Demo#include using namespace std; void print_vector(vector v){    cout

Suppose we have a list of numbers. We have to count the numbers that has even number of digit count. So if the array is like [12, 345, 2, 6, 7896], the output will be 2, as 12 and 7896 has even number of digitsTo solve this, we will follow these steps −Take the list and convert each integer into stringif the length of string is even, then increase count and finally return the count valueExampleLet us see the following implementation to get better understanding − Live Democlass Solution(object):    def findNumbers(self, nums):       str_num = map(str, nums)   ... Read More

Suppose we have an array A. There are few elements. Some elements are common. We have to return an element that is appearing more than 25% spaces in the array. So if A = [1, 2, 4, 4, 4, 4, 5, 5, 6, 6, 7, 7], Here 4 has occurred four times. This is more than 25% of 12 (size of the array)To solve this, we will follow these steps −Read elements and store their respective frequenciesIf the frequency is greater than 25% of the array size, then return the result.ExampleLet us see the following implementation to get better understanding ... Read More

Suppose we have one number. We have to find the sum of digits and product of digits. After that find the difference between sum and product. So if the number is 5362, then sum is 5 + 3 + 6 + 2 = 16, and 5 * 3 * 6 * 2 = 180. So 180 – 16 = 164To solve this take each digit and add and multiply one by one, then return the difference.ExampleLet us see the following implementation to get better understanding − Live Demo#include using namespace std; class Solution {    public:       int subtractProductAndSum(int n) {          int prod = 1;          int sum = 0;          for(int t = n;t;t/=10){             sum += t % 10;             prod *= t % 10;          }          return prod - sum;       } }; main(){    Solution ob;    cout

Suppose there are some points given as an array. We have to find the minimum time in seconds to visit all points. There are some conditions.In one second, it can move vertically, horizontally and diagonallyWe have to visit the points in the same order as they appear in the array.So if the points are [(1, 1), (3, 4), (-1, 0)], then output will be 7. If we check the sequence for the shortest route, the sequence will be (1, 1), (2, 2), (3, 3), (3, 4), (2, 3), (1, 2), (0, 1), (-1, 0)To solve this we will just find ... Read More

Suppose there are n and m which are the dimensions of a matrix. These are initialized by zeros. And indices are given where indices[i] = [ri, ci]. For each pair of [ri, ci] we have to increment all cells in row ri and column ci by 1. The output will be the number of cells with odd values in the matrix after applying the increment to all indices.To solve this, we will follow these steps −Initialize odd := 0, and x := row count of the matrixcreate a matrix matfor i in range 0 to xr = input[i, 0], c ... Read More

Suppose we have a function f that takes two parameters (x, y). We have to return all pairs of x and y, for which f(x, y) = z. The z is given as input, and x, y are positive integers. The function is constantly increasing function. So f(x, y) < f(x + 1, y) and f(x, y) < f(x, y + 1).To solve this we will perform straight-forward approach. Take i in range 1 to 1000, and j in range 1 to 1000, for all combinations of i, j, if f(i, j) = 0, then return true, otherwise false.Consider the ... Read More

Suppose we have a list of data-points consisting of (x, y) coordinates, we have to check whether the data-points are forming straight line or not. So if the points are like [(1, 2), (2, 3), (3, 4), (4, 5), (5, 6), (6, 7)], then they are forming straight line.To solve this, we will take the differences between each consecutive datapoints, and find the slope. For the first one find the slope. For all other points check whether the slope is same or not. if they are same, then simply return true, otherwise falseExampleLet us see the following implementation to get ... Read More

As we know that the balanced strings are those which have equal quantity of left and right characters. Suppose we have a balanced string s split it in the maximum amount of balanced strings. We have to return the maximum amount of splitted balanced strings. So if the string is “RLRRLLRLRL”, then output will be 4. as there are four balanced strings. “RL”, “RRLL”, “RL” and “RL” each substring has equal amount of L and R.To solve this, we will follow these steps −initialize cnt := 0, and ans := 0for i := 0 to size of the stringcnt := ... Read More

Suppose we have an array, and we need to check whether each element has a unique number of occurrences. If no such element exists, we return false; otherwise, we return true. For example, given the array [1, 1, 2, 2, 2, 3, 4, 4, 4, 4], the function will return true because no two elements have the same number of occurrences: 1 occurs twice, 2 occurs three times, 3 occurs once, and 4 occurs four times. Various Techniques to Find Unique Occurrences Following are the various techniques to find the unique occurrence of the elements in a list − ... Read More