Server Side Programming Articles - Page 1642 of 2646

Maximum absolute difference of value and index sums in C

Sunidhi Bansal
Updated on 17-Aug-2020 08:28:33

1K+ Views

We are given with an array of integers. The task is to calculate the maximum absolute difference of value and index sums. That is for each pair of indexes (i, j) in an array, we have to calculate | Arr[i] - A[j] | + |i-j| and find the maximum such sum possible. Here |A| means absolute value of A. If array has 4 elements then indexes are 0, 1, 2, 3 and unique pairs will be ( (0, 0), (1, 1), (2, 2), (3, 3), (0, 1), (0, 2), (0, 3), (1, 2), (1, 3), (2, 3) ).Input − Arr[] ... Read More

Sum of the series 2 + (2+4) + (2+4+6) + (2+4+6+8) + ... + (2+4+6+8+...+2n) in C++

sudhir sharma
Updated on 14-Aug-2020 14:16:51

325 Views

In this problem, we are given a number n which defines the nth term of the series 2 + (2+4) + (2+4+6) + (2+4+6+8) + ... + (2+4+6+8+...+2n). Our task is to create a program to find the sum of the series.Let’s take an example to understand the problem, Input n = 3OutputExplanation − sum = (2) + (2+4) + (2+4+6) = 2 + 6 + 12 = 20A simple solution to the problem is to use a nested loop. The inner loop finds the ith element of the series and then add up all elements to the sum variable.ExampleProgram to illustrate ... Read More

Sum of the series 1^1 + 2^2 + 3^3 + ... + n^n using recursion in C++

sudhir sharma
Updated on 01-Jul-2025 15:32:28

4K+ Views

In this article, we are given a mathematical series (1^1 + 2^2 + 3^3 + … + n^n) defined by a number n which defines the nth terms of the series. This series can be represented mathematically as: $$ \displaystyle\sum\limits_{k=1}^n k^k $$ The above series does not have any specific mathematical name but is generally referred to as the power tower series. Below is an example of the power tower series up to n. Example The following example calculates the sum of the given series 1^1 + 2^2 + 3^3 + … ... Read More

Sum of the Series 1/(1*2) + 1/(2*3) + 1/(3*4) + 1/(4*5) + ... in C++

sudhir sharma
Updated on 14-Aug-2020 14:04:06

694 Views

In this problem, we are given a number n which is the nth term of the series 1/(1*2) + 1/(2*3) +…+ 1/(n*(n+1)). Our task is to create a program to find the sum of the series.Let’s take an example to understand the problem, Input n = 3Output 0.75Explanation − sum = 1/(1*2) + 1/(2*3) + 1/(3*4) = ½ + ⅙+ 1/12 = (6+2+1)/12 = 9/12 = ¾ = 0.75A simple solution to the problem is using the loop. And commuting value for each element of the series. Then add them to the sum value.AlgorithmInitialize sum = 0 Step 1: Iterate from i = ... Read More

Sum of the series 1, 3, 6, 10… (Triangular Numbers) in C++

sudhir sharma
Updated on 14-Aug-2020 14:00:04

1K+ Views

In this problem, we are given a number n which is given the n of elements of the series 1, 3, 6, 10 … (triangular number). Our task is to create a program to calculate the sum of the series.Let’s brush up about triangular numbers before calculating the sum.Triangular numbers are those numbers that can be represented in the form of a triangle.A triangle is formed in such a way that the first row has one point, second has two, and so on.ExampleLet’s take an example to understand the problem, Inputn = 4OutputExplanation − sum = T1 + T2 + T3 ... Read More

Sum of the Series 1 + x/1 + x^2/2 + x^3/3 + .. + x^n/n in C++

sudhir sharma
Updated on 01-Jul-2025 15:33:23

2K+ Views

In this article, we are given a mathematical series. Our task is to write a program to find the sum of the series 1 + x/1 + x^2/2 + x^3/3 + .. + x^n/n. This can also be represented as: $$ 1+\displaystyle\sum\limits_{k=1}^n \left(\frac{x^k}{k}\right) $$ This series without starting 1 is known as the Taylor Expansion Series for -ln(1-x) where ln is the natural log. Example Here is an example of calculating the value of the given series: Input: x = 7, n = 4 Output: 747.08 ... Read More

Sum of the series 1 + (1+3) + (1+3+5) + (1+3+5+7) + + (1+3+5+7+....+(2n-1)) in C++

sudhir sharma
Updated on 14-Aug-2020 13:50:53

550 Views

In this problem, we are given an integer n. Our task is to create a program to find the sum of the series 1 + (1+3) + (1+3+5) + (1+3+5+7) + + (1+3+5+7+....+(2n-1)).From this series, we can observe that ith term of the series is the sum of first i odd numbers.Let’s take an example to understand the problem, Inputn = 3Output 14Explanation −(1) + (1+3) + (1+3+5) = 14A simple solution to this problem is using a nested loop and then add all odd numbers to a sum variable. Then return the sum.ExampleProgram to illustrate the working of our solution, ... Read More

Sum of the series 1 + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n) in C++

Ravi Ranjan
Updated on 16-Jul-2025 18:15:22

895 Views

In this article, we are given a number n. Our task is to write a program to calculate the sum of the series 1 + (1+2) + (1+2+3) + (1+2+3+4) + … + (1+2+3+4+...+n). This series can be represented mathematically as: $$ \displaystyle\sum\limits_{k=1}^n \displaystyle\sum\limits_{j=1}^k j $$ The above series is also known as tetrahedral number or triangular pyramidal number. A tetrahedral number is the number of points required to form a pyramid with a triangular base. Below is an example of the tetrahedral number series up to n. Scenario Consider the following example ... Read More

Sum of the series 1 / 1 + (1 + 2) / (1 * 2) + (1 + 2 + 3) / (1 * 2 * 3) + … + upto n terms in C++

Ravi Ranjan
Updated on 15-Jul-2025 18:29:51

1K+ Views

In this article, we are given an integer n. It defines the number of terms in the series: 1/1 + ( (1+2)/(1*2) ) + ( (1+2+3)/(1*2*3) ) + … + up to n terms. Our task is to write a program to calculate the sum of series 1/1 + (1+2)/(1*2) + (1+2+3)/(1*2*3) + … up to n terms. The above series can be represented as: $$ \sum_{k=1}^{n} \frac{\sum_{j=1}^{k} j}{k!} $$ Scenario The following example calculates the sum for the given series up to 4 terms: Input: n ... Read More

Sum of the series 0.7, 0.77, 0.777 … upto n terms in C++

sudhir sharma
Updated on 14-Aug-2020 13:31:55

269 Views

In this problem, we are given n terms of a number. The series is 0.7, 0.77, 0.777…. Our task is to create a program to find the sim of the series 0.7, 0.77, 0.777 … upto n terms.Let’s take an example to understand the problem, Input  4Output  Explanation −0.7 + 0.77 + 0.777 + 0.7777 = 3.0247To solve this problem, we will derive the formula for sum of series. Let’s find the general formula for it, sum = 0.7 + 0.77 + 0.777 + ... upto n terms sum = 7 (0.1 + 0.11 + 0.111 + … upto n ... Read More

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