Suppose we have a lowercase string s; we have to find the length of the longest palindromic subsequence in s.So, if the input is like s = "aolpeuvekyl", then the output will be 5, as the palindrome is "level".To solve this, we will follow these steps −n := size of sDefine a function dp() . This will take i, jif i is same as j, thenreturn 1otherwise when i > j, thenreturn 0otherwise, if s[i] is same as s[j], thenreturn 2 + dp(i + 1, j - 1)otherwise, return maximum of dp(i + 1, j) and dp(i, j - 1)return ... Read More

Suppose we have a 2D matrix, we have to find the length of the longest strictly increasing path. To traverse the path we can move up, down, left, or right nor diagonally.So, if the input is like246157339then the output will be 6, as The longest path is [1, 2, 4, 6, 7, 9]To solve this, we will follow these steps −n := row count of matrix , m := column count of matrix moves := a list of pairs to move up, down, left and right [[1, 0], [-1, 0], [0, 1], [0, -1]] Define a function dp() . This ... Read More

Suppose we have a binary tree. we have to find the length of the longest path whose sum is an even number.So, if the input is like image, then the output will be 5, as the path is like [5, 2, 4, 8, 5], sum = 24(even).To solve this, we will follow these steps −Define a function dfs() . This will take nodeif node is null, thenreturn a pair (0, -inf)(left_0, left_1) := dfs(left of node)(right_0, right_1) := dfs(right of node)if value of node is odd, thenans := maximum of ans, (left_1 + right_0 + 1) and (left_0 + right_1 ... Read More

Suppose we have three strings s1, s2, and s3, we have to find the length of their longest common subsequence.So, if the input is like s1 = "ababchemxde" s2 = "pyakcimde" s3 = "oauctime", then the output will be 4, as the longest common subsequence is "acme".To solve this, we will follow these steps −m := size of s1, n := size of s2, o := size of s3dp := a 3D matrix of size (o + 1) x (n + 1) x (m + 1)for i in range 1 to m, dofor j in range 1 to n, dofor ... Read More

Suppose we have a list of numbers called nums, we have to find the length of the longest arithmetic subsequence. As we know a sequence S[i] is an arithmetic sequence when S[i+1] - S[i] have the same value for every i in range (0 ≤ i < Size of S - 1).So, if the input is like nums = [1, 4, 7, 10, 13, 20, 16], then the output will be 6, the subsequence [1, 4, 7, 10, 13, 16] is an arithmetic because the difference between each consecutive element is 3.To solve this, we will follow these steps −n := size of arrif n

Suppose we have a list of numbers called nums, we have to find the size of the longest subsequence where the difference between two consecutive numbers alternate between positive and negative. And the first difference may be either positive or negative.So, if the input is like nums = [6, 10, 4, 2, 3, 9, 4, 7], then the output will be 6, as on possible required subsequence is [6, 10, 2, 9, 4, 7] and the differences are [4, -8, 7, -5, 3].To solve this, we will follow these steps &minuS;n := size of numsdp := a list of size ... Read More

Suppose we have a list of numbers called nums and that is sorted in non-decreasing order, we have to check whether it can be split into any number of subsequences such that each subsequence has at minimum length of 3 and that is consecutively increasing.So, if the input is like nums = [2, 3, 4, 4, 5, 6, 7], then the output will be True, as we can split the list to [2, 3, 4] and [4, 5, 6, 7].To solve this, we will follow these steps −counts := A map that contains elements of nums and its countsstarts := ... Read More

Suppose we have a list of numbers called nums, and another value k, we have to check whether it is possible to split the list into sublists lists such that each sublist has length ≥ k and that is strictly increasing. The list does not need to be split contiguously.So, if the input is like nums = [6, 7, 5, 10, 13] k = 2, then the output will be True, as the split is [5, 6] and [7, 10, 13].To solve this, we will follow these steps −c := A map that contains elements of nums and its countsmax_count := maximum of all frequencies of creturn True when max_count * k

Suppose we have a list of numbers called nums and another value k, we have to find the largest sum of three non-overlapping sublists of the given list of size k.So, if the input is like nums = [2, 2, 2, -6, 4, 4, 4, -8, 3, 3, 3] k = 3, then the output will be 27, as we can select the sublists [2, 2, 2], [4, 4, 4], and [3, 3, 3], total sum is 27.To solve this, we will follow these steps −P := [0]for each x in A, doinsert P[-1] + x at the end of ... Read More

Suppose we have a list of numbers called nums, now find two sets as their sums are same and maximum, then find sum value.So, if the input is like nums = [2, 5, 4, 6], then the output will be 6, as the sets are [2, 4] and [6].To solve this, we will follow these steps −sum := 0for each number i in nums, dosum := sum + in := size of numsDefine one 2D array dp of size (n + 1) x (2 * sum + 5) and fill with -1dp[0, sum] := 0for initialize i := 1, when ... Read More