A random 24 bit hash is just random 24 bits. You can generate these just using the random module. exampleimport random hash = random.getrandbits(24) print(hex(hash))OutputThis will give the output0x94fbee

A sequence is a positionally ordered collection of items, where each item can be accessed using its index number. The first element's index starts at 0. We use square brackets [] with the desired index to access an element in a sequence. If the sequence contains n items, the last item is accessed using the index n-1. In Python, there are built-in sequence types such as lists, strings, tuples, ranges, and bytes. These sequence types are classified into mutable and immutable. The mutable sequence types are those whose data can be changed after creation such, as list and byte arrays. ... Read More

Similar to the if statement syntax, if your while clause consists only of a single statement, it may be placed on the same line as the while header. Here are the syntax and example of a one-line for loop:for i in range(5): print(i)This will give the output:0 1 2 3 4

List comprehensions offer a concise way to create lists based on existing lists. When using list comprehensions, lists can be built by leveraging any iterable, including strings and tuples. list comprehensions consist of an iterable containing an expression followed by a for the clause. This can be followed by additional for or if clauses.Let’s look at an example that creates a list based on a string:hello_letters = [letter for letter in 'hello'] print(hello_letters)This will give the output:['h', 'e', 'l', 'l', 'o']string hello is iterable and the letter is assigned a new value every time this loop iterates. This list comprehension ... Read More

Python cannot iterate over an object that is not 'iterable'. The 'for' loop construct in python calls inbuilt functions within the iterable data-type which allow it to extract elements from the iterable.Since non-iterable data-types don't have these methods, there is no way to extract elements from them. And hence for loops ignore them.

You can handle exception inside a Python for loop just like you would in a normal code block. This doesn't cause any issues. For example,for i in range(5):    try:       if i % 2 == 0:          raise ValueError("some error")       print(i) except ValueError as e:    print(e)This will give the outputsome error 1 some error 3 some error

Here are some of the steps that you can follow to optimize a nested if...elif...else.1. Ensure that the path that'll be taken most is near the top. This ensures that not multiple conditions are needed to be checked on the most executed path.2. Similarly, sort the paths by most use and put the conditions accordingly.3. Use short-circuiting to your advantage. If you have a statement like:if heavyOperation() and lightOperation():Then consider changing it toif lightOperation() and heavyOperation():This will ensure that heavyOperation is not even executed if lightOperation is false. Same can be done with or conditions as well.4. Try flattening the ... Read More

This is a language agnostic question. Loops are there in almost every language and the same principles apply everywhere. You need to realize that compilers do most heavy lifting when it comes to loop optimization, but you as a programmer also need to keep your loops optimized.It is important to realize that everything you put in a loop gets executed for every loop iteration. The key to optimizing loops is to minimize what they do. Even operations that appear to be very fast will take a long time if the repeated many times. Executing an operation that takes 1 microsecond ... Read More

This error is coming because the interpreter is replacing the %d with i and then trying to add 1 to a str, ie, adding a str and an int. In order to correct this, just surround the i+1 in parentheses. exampleprint("\ Num %d" % (i+1))

This can be corrected by putting n+1 in brackets i.e. (n+1)for num in range(5):     print ("%d" % (num+1))Using %d casts the object following % to string. Since a string object can't be concatnated with a number (1 in this case) interpreter displays typeerror.