Suppose we have an expression that holds the ternary expression, we have to evaluate the result of the expression. It supports some values like T and F for True and False and “?” and “:” characters. There are some properties:The length of the given string must be less than or equal to 10000.The conditional expressions group right-to-left.The condition will always be either T or F. So the condition will never be a digit.The result of the expression will always evaluate to T or F.So for example, if the input is like “T ? T ? F : T : T”, ... Read More

Suppose we have a list of numbers called target. Now let us consider a list X with the same length as given list and X is filled with 1s. We can perform the following operation as many times as we want: Take any index i in X and set X[i] to the current sum of X. Finally check whether X can be turned into target or not.So, if the input is like target = [5, 9, 3], then the output will be True as initially X = [1, 1, 1], then update it with total sum 3, array will be ... Read More

Suppose we have a string s and another value k, we repeatedly delete the earliest k consecutive duplicate characters, and return the final string.So, if the input is like s = "paaappmmmma" k = 3, then the output will be "ma", as when we delete three "a"s to get "pppmmmma". Then we delete three "p"s to get "mmmma". Then delete three of the four "m"s to get "ma".To solve this, we will follow these steps:do the following steps infinitely, docount := 0chars := get the unique characters from sfor each character c in chars, doif k consecutive c is in ... Read More

Suppose we have a number n, we have to find the gray code for that given number (in other words nth gray code). As we know the gray code is a way of ordering binary numbers such that each consecutive number's values differ by exactly one bit. Some gray codes are: [0, 1, 11, 10, 110, 111, and so on]So, if the input is like n = 12, then the output will be 10 as the 12 is (1100) in binary, corresponding gray code will be (1010) whose decimal equivalent is 10.To solve this, we will follow these steps:Define a ... Read More

Suppose we have a 2D matrix where each row contains two values [height, count] these indicates the person has given height and there are 'count' number of people in front of them that are at least as tall as them. Now consider this queue is shuffled, we have to recover the original ordering of the queue.So, if the input is like224050then the output will be405022To solve this, we will follow these steps:N := row count of matrixrearrange matrix rows based on increasing height and decreasing countans := make a list of size N and initially all entries are nullfor each ... Read More

Suppose we have four lists of numbers A, B, C, and D, and also have a target value, we have to find the number of distinct quadruple (i, j, k, l) such that A[i] + B[j] + C[k] + D[l] is same as target.So, if the input is like A = [5, 4, 3] B = [8, 4] C = [6, 2] D = [4, 10] target = 23, then the output will be 3, the quadruples are [5, 8, 6, 4] [3, 4, 6, 10] [3, 8, 2, 10].To solve this, we will follow these steps:count := 0m := ... Read More

Suppose we have a binary list (1s and 0s in the list) and another value k. Each value in nums represents the state of a prison cell where 1 indicates occupied cell and 0 indicates empty cell. On each day when a cell has two adjacent cells that are either both occupied or both empty, then it becomes occupied. Otherwise, it becomes empty. So we have to find state of the prison cells after k number of days.So, if the input is like nums = [1, 0, 1, 0, 0, 0, 0, 0] k = 1, then the output will ... Read More

Suppose we have a list of numbers called nums and another value k, we have to check whether the list can be partitioned into pairs such that the sum of each pair is divisible by k.So, if the input is like nums = [4, 7, 2, 5] k = 6, then the output will be True, as we can partition the given list into pairs like (4, 2) and (8, 1) and their sums are divisible by 3.To solve this, we will follow these steps:if nums has even number of elements, thenreturn Falsecount := a list of size k and ... Read More

Suppose we have a list of numbers called nums. We can partition the list into some individual sublists then sort each piece. We have to find the maximum number of sublists we can partition to such that nums as a whole is sorted afterwards.So, if the input is like nums = [4, 3, 2, 1, 7, 5], then the output will be 2, as we can sort the sublists like [4, 3, 2, 1] and [7, 5]To solve this, we will follow these steps:count := 0main_sum := 0, sorted_sum := 0for each element x from nums and y from sorted ... Read More

Suppose we have a string s, we have to find the number of ways we can partition the string such that each part is a palindrome.So, if the input is like s = "xyyx", then the output will be 3, as we have splits like: ["x", "yy", "x"], ["x", "y", "y", "x"], ["xyyx"].To solve this, we will follow these steps:n := size of stable := a list of size n + 1 and fill it with 0table[0] := 1for i in range 0 to n, dofor j in range 0 to i - 1, dosub := s[from index j to ... Read More