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Programming Articles - Page 2469 of 3363
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In CLRS book the BFS algorithm is described using vectors and queue. We have to implement that algorithm using C++ STL. Let us see the algorithm at first.AlgorithmBFS(G, s) −begin for each vertex u in G.V - {s}, do u.color := white u.d := infinity u.p := NIL done s.color := green s.d := 0 s.p := NIL Q := NULL insert s into Q while Q is not null, do u = delete from Q for ... Read More
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Here we will see the Betrothed number. This is a pair of numbers, such that the sum of the proper divisors of one number is one more than the other number. We have to find these pairsFor an example, the pair is like (48, 75). So the divisors of 48 is {1, 2, 3, 4, 6, 8, 12, 16, 24} and sum is 76. Similarly, the divisors of 75 is {1, 3, 5, 15, 25} so sum is 49.AlgorithmBetrothedPairs (n) −begin for num in range 1 to n, do sum := 1 for ... Read More
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Here we will see the Baum Sweet Sequence. This sequence is one binary sequence. If a number n has an odd number of contiguous 0s, then nth bit will be 0, otherwise nth bit will be 1.We have a natural number n. Our task is to find the n-th term of Baum Sweet sequence. So we have to check whether it has any consecutive block of zeros of odd length.If the number is 4 then the term will be 1, because 4 is 100. So it has two (even) number of zeros.AlgorithmBaumSweetSeqTerm (G, s) −begin define bit sequence seq ... Read More
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Here we will see how the auxiliary space is required for recursive function call. And how it is differing from the normal function call?Suppose we have one function like below −long fact(int n){ if(n == 0 || n == 1) return 1; return n * fact(n-1); }This function is recursive function. When we call it like fact(5), then it will store addresses inside the stack like below −fact(5) ---> fact(4) ---> fact(3) ---> fact(2) ---> fact(1)As the recursive functions are calling itself again and again, addresses are added into stack. So if the function is ... Read More
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Here we will see one interesting problem. We have one array with N elements. We have to perform one query Q as follows −The Q(start, end) indicates that number of times a number ‘p’ is occurred exactly ‘p’ number of times from start to end.So if the array is like: {1, 5, 2, 3, 1, 3, 5, 7, 3, 9, 8}, and queries are −Q(1, 8) − Here the 1 is present once, and 3 is present 3 times. So the answer is 2Q(0, 2) − Here the 1 is present once. So the answer is 1Algorithmquery(s, e) −Begin ... Read More
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Here we will see one problem, where one rectangle is given. We have to find the area of largest rhombus that can be inscribed in the rectangle. The diagram will be look like below −The length of the rectangle is ‘l’ and breadth is ‘b’ So the area of the rhombus is −Source Code#include #include using namespace std; float area(float l, float b) { if (l < 0 || b < 0) //if the values are negative it is invalid return -1; float area = (l*b) /2; return area; } int main() { float l = 20.0, b = 7; cout
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Suppose we have one square whose side is ‘a’. We will make more squares by attaching the mid-points of the squares repeatedly. The number of repetition is n times. We have to find the area of nth square.As the side of the outer square is ‘a’, then area isNow using Pythagorean theorem, we can get the area of the second rectangle is −Similarly, area of 3rd square is −Using this we can understand that the area of nth square is −Example#include #include using namespace std; float area(float a, float n) { if (a < 0 ) //if ... Read More
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Suppose one rectangle is given. We know the length L and breadth B of it. We have to find the area of largest triangle that can be inscribed within that rectangle −The largest triangle will always be the half of the rectangle. So it will beExample#include #include using namespace std; float area(float l, float b) { if (l < 0 || b < 0 ) //if the valuse are negative it is invalid return -1; float area = (l*b)/2; return area; } int main() { float a = 10, b = 8; cout
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A yield() method is a static method of Thread class and it can stop the currently executing thread and will give a chance to other waiting threads of the same priority. If in case there are no waiting threads or if all the waiting threads have low priority then the same thread will continue its execution. The advantage of yield() method is to get a chance to execute other waiting threads so if our current thread takes more time to execute and allocate processor to other threads. Syntax public static void yield() Example class MyThread extends Thread { public void run() { ... Read More
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Here we will see the area of largest rectangle that can be inscribed in an ellipse. The rectangle in ellipse will be like below −The a and b are the half of major and minor axis of the ellipse. The upper right corner of the rectangle is (x, y). So the area isNow, after making this equation as f(x) and maximizing the area, we will get the area asExample#include #include using namespace std; float area(float a, float b) { if (a < 0 || b < 0 ) //if the valuse are negative it is invalid ... Read More