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Programming Articles - Page 2217 of 3366
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Suppose, one binary tree is given. It has leaf nodes at different levels. Another pointer is given, that is pointing to a node. We have to find the distance to the nearest leaf node from the pointed node. Consider the tree is like below −Here leaf nodes are 2, -2 and 6. If the pointer is pointing to node -5, The nearest nodes from -5 will be at distance 1.To solve this, we will traverse the subtree rooted with the given node, and find the closest leaf in the subtree, then store the distance. Now traversing tree starting from the ... Read More
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Consider we have the side of the isosceles triangle, our task is to find the area of it and the altitude. In this type of triangle, two sides are equal. Suppose the sides of the triangle are 2, 2 and 3, then altitude is 1.32 and the area is 1.98.Altitude(h)=$$\sqrt{a^{2}-\frac{b^{2}}{2}}$$Area(A)=$\frac{1}{2}*b*h$Example Live Demo#include #include using namespace std; float getAltitude(float a, float b) { return sqrt(pow(a, 2) - (pow(b, 2) / 4)); } float getArea(float b, float h) { return (1 * b * h) / 2; } int main() { float a = 2, b = 3; cout
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In this tutorial, we will be discussing a program to print an inverse pyramid character pattern.For this we will be provided with the number of rows containing in the inverted pyramid triangle. Our task is to print the alphabets in the given number of rows to develop the shape of an inverse pyramid.Example Live Demo#include using namespace std; //printing the inverse pyramid pattern void inv_pyramid(int n){ int i, j, num, gap; for (i = n; i >= 1; i--) { for (gap = n - 1; gap >= i; gap--) { cout
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Suppose we have a curve like y = x(A - x), we have to find the tangent at a given point (x, y) on that curve. Here A is an integer number, x and y are also integers.To solve this, we have the check that the given point is on the curve or not, if so, then find the differentiation of that curve, so it will be −$$\frac{\text{d}y}{\text{d}x}=A-2x$$Then put x and y into the dy/dx, then find the tangent using this equation −$$Y-y=-\lgroup\frac{\text{d}y}{\text{d}x}\rgroup*\lgroup X-x \rgroup$$Example Live Demo#include using namespace std; void getTangent(int A, int x, int y) { int differentiation ... Read More
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Consider we have an array A with n elements. We have to find the total sum of the sum of all the subsets of the array. So if the array is like A = [5, 6, 8], then it will be like −SubsetSum5566885, 6116, 8145, 8135, 6, 819Total Sum76As the array has n elements, then we have a 2n number of subsets (including empty). If we observe it clearly, then we can find that each element occurs 2n-1 timesExample Live Demo#include #include using namespace std; int totalSum(int arr[], int n) { int res = 0; for (int i = ... Read More
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In this tutorial, we will be discussing a program to print all the numbers divisible by 3 and 5 less than the given number.For this we will be given with a number say N. Our task is to print all the numbers less than N which are divisible by both 3 and 5.Example Live Demo#include using namespace std; //printing the numbers divisible by 3 and 5 void print_div(int N){ for (int num = 0; num < N; num++){ if (num % 3 == 0 && num % 5 == 0) cout
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Suppose, we have a number n, our task is to find the sum of digits in then!. Consider n = 5, then n! = 120. So the result will be 3.To solve this problem, we will create a vector to store factorial digits and initialize it with 1. Then multiply 1 to n one by one to the vector. Now sum all the elements in the vector and return the sumExample Live Demo#include #include using namespace std; void vectorMultiply(vector &v, int x) { int carry = 0, res; int size = v.size(); for (int i = 0 ; ... Read More
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In this tutorial, we will be discussing a program to print all the substring of a given string.For this we will be given with a string or an array of characters. Our task is to print all the substrings of that particular string.Example Live Demo#include using namespace std; //printing all the substrings void print_substr(char str[], int n){ for (int len = 1; len
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Suppose we have an array of n elements called A. We have to print the remainder after multiply all the numbers divided by n. Suppose A = [100, 10, 5, 25, 35, 14], and n = 11. The output is 9. So the value of 100 * 10 * 5 * 25 * 35 * 14 mod 11 = 9.First, we have to take the remainder of each number, then multiply the remainder with the current result. After multiplication, again take the remainder to avoid overflow.Example Live Demo#include #include using namespace std; int getRemainder(int a[], int size, int n) { int mul = 1; for(int i = 0; i
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In this tutorial, we will be discussing a program to print all palindromes in a given range.For this we will be given the mathematical range in which the palindromes are to be found. Our task is to find all the palindromes in that range and print it back.Example Live Demo#include using namespace std; //checking if the number is a palindrome int is_palin(int n){ int rev = 0; for (int i = n; i > 0; i /= 10) rev = rev*10 + i%10; return (n==rev); } void countPal(int min, int max){ for (int i = min; i