Data Structure
 Networking
 RDBMS
 Operating System
 Java
 MS Excel
 iOS
 HTML
 CSS
 Android
 Python
 C Programming
 C++
 C#
 MongoDB
 MySQL
 Javascript
 PHP
- Selected Reading
 - UPSC IAS Exams Notes
 - Developer's Best Practices
 - Questions and Answers
 - Effective Resume Writing
 - HR Interview Questions
 - Computer Glossary
 - Who is Who
 
Programming Articles - Page 1705 of 3366
 
			
			933 Views
Suppose we have a list of numbers called nums, we have to check whether we can split the list into 1 or more groups such that: 1. Size of each group is greater than or equal to 2. 2. Sizes of all groups are same. 3. All the numbers present in each group are the same.So, if the input is like [3, 4, 6, 9, 4, 3, 6, 9], then the output will be True.To solve this, we will follow these steps −counts := a map where each key are distinct element and values are their frequenciestemp := 0for each ... Read More
 
			
			283 Views
Suppose we have a list of positive numbers called nums, we have to find the largest positive number that divides each of the number.So, if the input is like [14,28,70,56], then the output will be 14.To solve this, we will follow these steps −ans := first element of numsfor each x in nums, doans := gcd of ans and xreturn ansLet us see the following implementation to get better understanding −Exampleimport math class Solution: def solve(self, nums): ans = nums[0] for x in nums: ans = math.gcd(ans, x) return ans ob = Solution() print(ob.solve([14,28,70,56]))Input[14,28,70,56]Output14
 
			
			5K+ Views
Suppose we have a number n, we have to generate a list of all prime numbers smaller than or equal to n in ascending order. We have to keep in mind that 1 is not a prime number.So, if the input is like 12, then the output will be [2, 3, 5, 7, 11].To solve this, we will follow these steps −sieve := a list of size n+1 and fill with Trueprimes := a new list, initially blankfor i in range 2 to n, doif sieve[i] is True, theninsert i at the end of primesfor j in range i to ... Read More
 
			
			98 Views
Suppose we have list of intervals and another input time. In each interval the structure is [start, end], this is representing the times when a programmer worked. We have to find the number of programmers that were working at time.So, if the input is like interval = [[2, 6], [4, 10], [5, 9], [11, 14]], time = 5, then the output will be 3 as at time 5, there are three programmers, working [2, 6], [4, 10], [5, 9]To solve this, we will follow these steps −count := 0for each interval in intervals, doif start of interval = time, thencount ... Read More
 
			
			110 Views
Suppose we have a list of words, we have to frame it in a rectangular region, line by line. See the example for better understanding.So, if the input is like ['hello', 'world', 'python', 'programming', 'nice'], then the output will be*************** * hello * * world * * python * * programming * * nice * ***************To solve this, we will follow these steps −l:= length of maximum size word in the arrayst:= put star (l+4) timesfor each i in words, dost := st concatenate '*' concatenate i then add ... Read More
 
			
			800 Views
Suppose we have a binary matrix mat. We have to select each row in matrix, then reverse the row. After that, flip each bit (0 to 1 and 1 to 0).So, if the input is like110010001then the output will be100101011To solve this, we will follow these steps −track:= 0for each row in mat, doreverse the rowtracker := 0for each val in row, doif val is 1, thenmat[track, tracker] := 0otherwise, mat[track, tracker] := 1tracker := tracker + 1track := track + 1return matLet us see the following implementation to get better understanding −Example Live Democlass Solution: def solve(self, mat): ... Read More
 
			
			5K+ Views
Suppose we have a number n. We have to find a string that is representing all numbers from 1 to n, but we have to follow some rules.When the number is divisible by 3, put Fizz instead of the numberWhen the number is divisible by 5, put Buzz instead of the numberWhen the number is divisible by 3 and 5 both, put FizzBuzz instead of the numberTo solve this, we will follow these steps −For all number from 1 to n, if number is divisible by 3 and 5 both, put “FizzBuzz”otherwise when number is divisible by 3, put “Fizz”otherwise ... Read More
 
			
			188 Views
Suppose we have a lowercase string s, we have to check whether it's possible to pick some subsequence of characters in s such that − 1. The difference of any two successive indexes of the characters is same 2. The characters form the string "programmingquestion"So, if the input is like "pzrzozgzrzazmzmziznzgzqzuzezsztzizozn", then the output will be TrueTo solve this, we will follow these steps −p := An array of indices where p is presentr := An array of indices where r is presentfor each j in p, dofor each k in r, doif k > j, thenif "programmingquestion" in substring ... Read More
 
			
			614 Views
Suppose we have a list of numbers called nums, we have to exchange every consecutive even integer with each other.So, if the input is like nums = [4, 5, 6, 8, 10], then the output will be [6, 5, 4, 10, 8]To solve this, we will follow these steps −temp := nullfor i in range 0 to size of nums, doif nums[i] mod 2 is same as 0, thenif temp is not null, thenexchange nums[i], nums[temp]temp := nullotherwise, temp := ireturn numsLet us see the following implementation to get better understanding −Example Live Democlass Solution: def solve(self, nums): ... Read More
 
			
			175 Views
Suppose we have a string s, we have to remove all “y” and “xz” in the string in one iteration.So, if the input is like s = "xyxxzyyxxzx", then the output will be xxxxTo solve this, we will follow these steps −To solve this, we will follow these steps −temp := string after removing xzreturn temp after removing yLet us see the following implementation to get better understanding −Example Live Democlass Solution: def solve(self, s): return s.replace("xz","").replace("y","") ob = Solution() print(ob.solve("xyxxzyyxxzx"))Input"xyxxzyyxxzx"Outputxxxx