Programming Articles - Page 1421 of 3366

SolutionTo solve this, we will follow the steps given below −Define an empty listCreate a for loop and set range from 100 to 150Set another for loop to access the values from 2 to range of values and find the factors, if nothing is found then add to the list. It is defined below, for i in range(100, 150):    for j in range(2, i):       if(i % j == 0):          break    else:       l.append(i)Set random sample value as 5 and assign into the list then finally create a Series.data = ... Read More

Input −Assume, you have a series, 0    1.0 1    2.0 2    3.0 3    NaN 4    4.0 5    NaNOutput − And, the result for NaN index is, index is 3 index is 5SolutionTo solve this, we will follow the steps given below −Define a Series.Create for loop and access all the elements and set if condition to check isnan(). Finally print the index position. It is defined below, for i, j in data.items(): if(np.isnan(j)):    print("index is", i)ExampleLet us see the following implementation to get a better understanding.import pandas as pd import numpy as np l ... Read More

Input − Assume, you have a Series, 0    apple 1    oranges 2    alpha 3    aroma 4    betaOutput − And, the result for elements start and endswith ‘a’.2    alpha 3    aromaSolution 1Define a Series.Create regular expression to check start and endswith ‘a’r'^[a]$|^([a]).*\1$'Create an empty list and set for loop and set if condition inside to check the pattern. It is defined below, for i in data:    if(re.search(exp, i)):       ls.append(i)Finally, check the series using isin().ExampleLet us see the following implementation to get a better understanding.import pandas as pd import re l ... Read More

Input − Assume, you have a series, 0    1 1    2 2    3 3    4Output − And, the result for the power of all elements in a series is, 0    1 1    4 2    27 3    256Solution 1Define a Series.Create transform method inside apply lambda power value. It is defined below, data.transform(lambda x:x**x)data.transform(lambda x:x**x)Solution 2Define a Series.Create an empty list. Create for loop, iter all the items. Append elements to the list. It is defined below, for i, j in data.items():    ls.append(m.pow(j, j))Finally, convert the list into Series.ExampleLet us see the ... Read More

Input −Assume, you have a series, 0    This is pandas 1    python script 2    pandas seriesOutput −And, the result after removing an element contains exactly two spaces, 1    python script 2    pandas seriesSolution 1Define a Series.Create lambda filter method to apply a regular expression to find the total number of spaces not equal to 2 as follows −pd.Series(filter(lambda x:len(re.findall(r" ", x))!=2, data))Finally, check the list of values to the series using isin().Solution 2Define a Series.Create for loop to iter the elements one by one and set if condition to count the spaces equal to 2. ... Read More

Input − Assume, you have a Series,0 abdef 1 ijkl 2 Abdef 3 oUijlOutput − And the result for all the elements in descending order,3 oUijl 1 ijkl 0 abdef 2 AbdefSolutionTo solve this, we will follow the steps given below −Define a SeriesApply sort_values method with the argument as ascending = False. It is defined below,data.sort_values(ascending=False)ExampleThe complete code listing is as follows,import pandas as pd l=["abdef","ijkl","Abdef","oUijl"] data=pd.Series(l) print("original series: ", data) print(data.sort_values(ascending=False))Output3    oUijl 1    ijkl 0    abdef 2    Abdef

Input − Assume, you have a Series, a    abc b    123 c    xyz d    ijkSolutionTo solve this, we will follow the steps given below −Define a SeriesGet the index from userSet the if condition to check the value is digit or not. It is defined below, if(data[x].isdigit()):    print("digits present") else:    print("not present")ExampleLet us see the following implementation to get a better understanding.import pandas as pd dic = {'a':'abc', 'b':'123', 'c':'xyz', 'd':'ijk'} data = pd.Series(dic) x = input("enter the index : ") if(data[x].isdigit()):    print("digits present") else:    print("not present")Outputenter the index : a not ... Read More

Input − Assume, you have a series,0    12 1    13 2    15 3    20 4    19 5    18 6    11Output − The result for the elements between 10 to 15 as,0    12 1    13 2    15 6    11Solution 1Define a SeriesCreate an empty list.Create for loop to access all the elements one by one and set if condition to compare the value from above or equal to 10 and below or equal to 15. Append matched values to an empty list as follows −for i in range(len(data)): if(data[i]>=10 and data[i]=10 and data[i]

Input − Assume, you have a series, 0    1 1    2 2    python 3    3 4    4 5    5 6    6.5Output −Total number of integer, float and string elements are, integer count: 5 float count: 1 string count: 1SolutionTo solve this, we will follow the steps given below −Define a Series.Create lambda filter method to extract the length of an integer value as follows, len(pd.Series(filter(lambda x:type(x)==int, data)Create lambda fliter method to extract length of float value as follows, len(pd.Series(filter(lambda x:type(x)==float, data)Create lambda fliter method to extract length of string value as follows, len(pd.Series(filter(lambda ... Read More

Input − Assume, you have the following series, 0    1 1    2 2    3 3    4 4    5The above series contains no duplicate elements. Let’s verify using the following approaches.Solution 1Assume, you have a series with duplicate elements0    1 1    2 2    3 3    4 4    5 5    3Set if condition to check the length of the series is equal to the unique array series length or not. It is defined below, if(len(data)==len(np.unique(data))):    print("no duplicates") else:    print("duplicates found")Exampleimport pandas as pd import numpy as np data = ... Read More