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Microcontroller Articles
Page 23 of 33
RST7.5 pin in 8085
RST7.5 pin is an input which is edge-sensitive. Peripherals uses it for sending a pulse, rather than a sustained high level, for the interruption of the processor. Internal to 8085 we have a flip-flop which gets connected to the interrupt pin RST7.5. We set this flip-flop to 1, when a positive-going edge occurs on the input RST 7.5. The waveform of pin RST7.5 and output Q of RST7.5 flip-flop is shown in the Fig.Internal interrupt signal RST7.5 has a priority higher than the internal interrupt signals of RST6.5, RST5.5 and INTR. As we can see from fig the RST7.5 internal interrupt ...
Read MoreSubtract content of two ports by interfacing 8255 with 8085 microprocessor
In this program we will see how to perform subtraction by using ports to take data and send the result into the port.Problem StatementWrite 8085 Assembly language program for interfacing between 8085 and 8255. Here Port A and Port B are holding two values, take the numbers from port A and B, subtract B from A, and send the result at port C.DiscussionThe task is very simple. At first we have to setup the control word register of 8255 chip. After that we will take the input from port A and B, add the content, and send it to port ...
Read More8086 program to convert ASCII to BCD number
In this program we will see how to find the equivalent BCD number from an ASCII value.Problem StatementWrite 8086 Assembly language program to find the equivalent BCD number from an ASCII value. The number is stored at memory location 2050 and store the result at memory location 3050.DiscussionThis program can change ASCII value of a number to its BCD (Decimal) form. The ASCII values of the numbers are like below:ASCII (in Hex)30313233343536373839BCD00010203040506070809 From this table we can easily find that the last nibble of the ASCII value is actually the BCD equivalent. So to take the last nibble we have masked ...
Read MoreTrap interrupt pin in 8085
A non-maskable interrupt is a Trap Interrupt which implies that whenever this pin gets activated, the 8085 always gets interrupted even if the state of 8085 is in DI. The input of Trap input is level sensitive and edge sensitive. Hence the Trap line always makes a transition from 0 to 1, and remains in state 1 until the end of the execution of an instruction for the interruption of 8085. A vectored-interrupt in 8085 is a TRAP. The starting address of 8085 is known by itself the of the ISS as 4.5 * 8 = 0024H. Hence we name the ...
Read More8086 program to determine largest number in an array of n numbers
In this program we will see how to find the largest number in a given array.Problem StatementWrite 8086 Assembly language program to find the largest number in a given array, which is starts from memory offset 501. The size of the series is stored at memory offset 500. Store the largest number at memory offset 600.DiscussionAt first we are taking the size of the array from memory offset 500. Then using that size, we are initializing the counter to read and check all the numbers. We are taking the first number into AL, then check each number and compare it ...
Read MoreNeed for masking in 8085
Let us say that the 8085 which is interrupted because of RST6.5 pin and has been branched to the ISS for the pin RST6.5. Then, except the DI instruction at the beginning of this ISS, all the interrupts gets disabled except TRAP. So, even if RST7.5 pin is in activated state in the middle of the execution of RST6.5 ISS, the interruption of 8085 will not occur due to RST7.5. Actually a higher priority interrupt is RST7.5, but the lower priority interrupt ISS cannot be interrupted by it of RST6.5. We solve this problem by specifically having the instruction which ...
Read MoreProgram for simulation of throwing a die in 8085 Microprocessor
Write an 8085 assembly language program to simulate the throw of a die using an interrupt.We have a counter for this program, which counts the ranges from 1 to 6, and again repeats the sequence of count in a matter which is endless in an infinite loop. The die throwing getting the head and tail probability gets simulated by pressing the key ‘Vect Intr’ on the keyboard. The branching of 8085 branches to RST7.5 ISS. Here, the current value of the counter gets is displayed in the data field, which controls and returns to the main program for the continuation ...
Read More8086 program to find the min value in a given array
In this program we will see how to find the minimum number in a given array.Problem StatementWrite 8086 Assembly language program to find the minimum number in a given array, which is starts from memory offset 501. The size of the series is stored at memory offset 500. Store the minimum number at memory offset 600.DiscussionAt first we are taking the size of the array from memory offset 500. Then using that size, we are initializing the counter to read and check all the numbers. We are taking the first number into AL, then check each number and compare it ...
Read MoreProgram for simulating a stopwatch in 8085 Microprocessor
We write an 8085 assembly language program just to simulate a stopwatch for displaying minutes and seconds in the address field. There exists a provision to stop the stopwatch, along with the display for continuation to show the time just previous to the stop command.FILE NAME STOPWACH.ASM PRESSING THE ‘VECT INTR’ KEY STOPS THE STOPWATCH, WITH STATIONARY DISPLAY ORG C000H CURAD: EQU FFF7H UPDAD: EQU 06BCH RESET: LXI H, 0000H REPEAT: SHLD CURAD CALL UPDAD; Display time present in HL in the address field MVI A, 00011011B SIM ; Unmask RST7.5, Reset RST7.5 flip flop EI ; Enable interrupt ...
Read More8086 program to sort an integer array in ascending order
In this program we will see how to sort array elements in ascending order.Problem StatementWrite 8086 Assembly language program to sort the elements in a given array, which is starts from memory offset 501. The size of the series is stored at memory offset 500.DiscussionHere we are sorting the number in bubble sorting technique. In this sorting technique there will be n passes for n different numbers. In ith pass the ith largest element will be placed at the end. This is comparison based sort. We taking two consecutive numbers, compare them, and then swap them if the numbers are ...
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