Found 7197 Articles for C++

What are different types of constants in C++?

Lakshmi Srinivas
Updated on 11-Feb-2020 08:09:49

795 Views

There are no types of constants in C++. It's just that you can declare any data type in C++ to be a constant. If a variable is declared as constant using the const keyword, you cannot reassign its value. Example#include using namespace std; int main() {    const int i = 5;    // Now all of these operations are illegal and    // will cause an error:    i = 10;    i *= 2;    i++;    i--;    //...    return 0; }

How to define constants in C++?

Arushi
Updated on 11-Feb-2020 08:08:30

737 Views

You can define constants in C++ by adding the const qualifier before the declaration of the variable. Example#include using namespace std; int main() {    const int x = 9;    x = 0;    return 0; }This will define the constant variable x. But it will throw an error as we are trying to rewrite the value of a constant.

What are the rules to declare variables in C++?

Sharon Christine
Updated on 11-Feb-2020 08:06:43

12K+ Views

To declare a variable, you need to know what data type it is going to be of and what its name would be. The variable name has constraints on what you can name it. Following are the rules for naming variables − Variable names in C++ can range from 1 to 255 characters. All variable names must begin with a letter of the alphabet or an underscore(_). After the first initial letter, variable names can also contain letters and numbers.   Variable names are case sensitive. No spaces or special characters are allowed. You cannot use a C++ keyword (a reserved word) as a variable name.Here ... Read More

What are the basic rules for defining variables in C++?

Arjun Thakur
Updated on 11-Feb-2020 08:04:48

1K+ Views

To declare a variable, you need to know what data type it is going to be of and what its name would be. The variable name has constraints on what you can name it. Following are the rules for naming variables −Variable names in C++ can range from 1 to 255 characters.All variable names must begin with a letter of the alphabet or an underscore(_).After the first initial letter, variable names can also contain letters and numbers.  Variable names are case sensitive.No spaces or special characters are allowed.You cannot use a C++ keyword (reserved word) as a variable name.Here are ... Read More

What is type inference in C++?

Samual Sam
Updated on 11-Feb-2020 08:02:36

779 Views

Type inference or deduction refers to the automatic detection of the data type of an expression in a programming language. It is a feature present in some strongly statically typed languages. In C++, the auto keyword(added in C++ 11) is used for automatic type deduction. For example, you want to create an iterator to iterate over a vector, you can simply use auto for that purpose. Example#include #include using namespace std; int main() {    vector arr(10);    for(auto it = arr.begin(); it != arr.end(); it ++) {       cin >> *it;    }    return 0; }In the ... Read More

What is the relation between auto and decltype in C++?

Revathi Satya Kondra
Updated on 13-Jun-2025 12:57:14

1K+ Views

The auto and decltype serve different purposes so they don't map one-to-one. The auto is a keyword in C++11 and later that is used for automatic type deduction. The decltype type specifier yields the type of a specified expression. Unlike auto that deduces types based on values being assigned to the variable, decltype deduces the type from an expression passed to it. The value returned by decltype can directly be used to define another variable. The auto follows the rules of template parameter deduction. You can read more about these rule at Template Argument Deduction While decltype has rules it ... Read More

What are auto and decltype in C++?

Lakshmi Srinivas
Updated on 11-Feb-2020 07:56:41

385 Views

Auto is a keyword in C++11 and later that is used for automatic type deduction. Type inference or deduction refers to the automatic detection of the data type of an expression in a programming language. It is a feature present in some strongly statically typed languages. For example, you want to create an iterator to iterate over a vector, you can simply use auto for that purpose. example#include #include using namespace std; int main() {    vector arr(10);    for(auto it = arr.begin(); it != arr.end(); it ++) {       cin >> *it;    }    return 0; }In ... Read More

How do we initialize a variable in C++?

karthikeya Boyini
Updated on 11-Feb-2020 07:54:11

222 Views

You can initialize a variable using the assignment operator or use its constructor when initializing it. For example,int i = 0; MyClass instance(1, "Hello");It will be automatically initialized ifIt's a class/struct instance in which the default constructor initializes all primitive types; like MyClass instance; You use array initializer syntax, e.g. int a[10] = {} (all zeroed) or int a[10] = {1,2}; (all zeroed except the first two items: a[0] == 1 and a[1] == 2) It is a global/extern variable It is defined static

What is type deduction in C++?

Revathi Satya Kondra
Updated on 13-Jun-2025 12:54:09

1K+ Views

Type inference (or type deduction) refers that the compiler can figure out the datatype of a variable or expression automatically, without the programmer needing to write it out. This feature is available in many strongly typed languages like C++, where the type system is strict but the compiler helps to reduce the typing effort. Following is the simple example to understand the type deduction in C++. #include using namespace std; int main() { // Let the compiler deduce the type from the value auto number = 50; // int auto pi = 3.14; // double cout

What does a semicolon do after a C++ class name?

Swarali Sree
Updated on 11-Feb-2020 07:51:53

450 Views

If you have statements like −Class Person;This is a forward declaration. It lets the following code know that there is are classes with the name Person. This satisfies the compiler when it sees these names used. Later the linker will find the definition of the classes.

Advertisements