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Big Data Analytics Articles
Page 58 of 135
Find MongoDB documents where all objects in array have specific value?
To find MongoDB documents where all objects in an array have a specific value, use the $not operator combined with $elemMatch to exclude documents that contain any non-matching values. Syntax db.collection.find({ "arrayField": { "$not": { "$elemMatch": { "field": { $ne: "desiredValue" } } } } }); Sample Data db.demo74.insertMany([ ...
Read MoreIn MongoDB, what is the most efficient way to get the first and last document?
To get the first and last document in MongoDB, use aggregate() with $first and $last operators within a $group stage. This efficiently retrieves both documents in a single operation. Syntax db.collection.aggregate([ { $group: { _id: null, first: { $first: "$$ROOT" }, last: { $last: "$$ROOT" } ...
Read MoreMongoDB query on nth element (variable index) of subdocument array
To query the nth element (variable index) of a subdocument array in MongoDB, use $expr with $let to define a temporary variable that extracts the element at a specific index using $arrayElemAt. Syntax db.collection.find({ $expr: { $let: { vars: { variableName: { $arrayElemAt: [ "$arrayField", index ] } }, in: { $eq: [ "$$variableName.field", "value" ] } ...
Read MoreHow to calculate sum of string in MongoDB?
To calculate sum of string values in MongoDB, use the aggregate pipeline with $group and $sum operators. Convert string numbers to integers using $toInt before summing them. Syntax db.collection.aggregate([ { $group: { _id: null, totalSum: { $sum: { $toInt: "$fieldName" } ...
Read MoreIs there a MongoDB query to concatenate deep sub-lists?
To concatenate deep sub-lists in MongoDB, use the $unwind operator in an aggregation pipeline to flatten nested arrays, then apply additional transformations like sorting, limiting, and reshaping the results. Syntax db.collection.aggregate([ { $unwind: "$arrayField1" }, { $unwind: "$arrayField1.nestedArray" }, { $sort: { "arrayField1.nestedArray.field": 1 } }, { $replaceRoot: { newRoot: "$arrayField1.nestedArray" } } ]); Sample Data db.demo70.insertOne({ "first": [ { ...
Read MoreMongoDB, finding all documents where property id equals to record id?
To find all documents where a property id equals the record's _id in MongoDB, use the $where operator with a JavaScript function that compares the field values after converting them to strings. Syntax db.collection.find({ $where: function(){ return this._id.toString() == this.fieldName.toString(); } }); Sample Data db.demo69.insertMany([ { "_id": ObjectId("507c7f79bcf86cd7994f6c0e"), "Details": { ...
Read MoreMongoDB aggregate query to sort
The $sort stage in MongoDB aggregation pipeline sorts documents by one or more fields. Use 1 for ascending order and -1 for descending order. You can combine it with other stages like $match to filter and sort results. Syntax db.collection.aggregate([ { $match: { field: value } }, { $sort: { field: 1 } } // 1 for ascending, -1 for descending ]); Sample Data db.demo67.insertMany([ { "StudentAge": 23 }, { "StudentAge": 21 }, ...
Read MoreHow to get the index of an array element in older versions on MongoDB?
To get the index of an array element in older versions of MongoDB, use the $indexOfArray aggregation operator. This operator returns the position (0-based index) of the first occurrence of a specified value in an array, or -1 if the value is not found. Syntax db.collection.aggregate([ { $project: { fieldName: { $indexOfArray: ["$arrayField", "searchValue"] } } } ]); Sample ...
Read MoreMongoDB aggregation to sum product price with similar IDs
To sum product prices with similar IDs in MongoDB, use the $group stage in aggregation pipeline with $sum operator. This groups documents by a specified field and calculates the total for each group. Syntax db.collection.aggregate([ { $group: { _id: "$groupingField", totalFieldName: { $sum: "$fieldToSum" } } } ]); ...
Read MoreHow to properly use 'exist' function in MongoDB like in SQL?
To check for existence of a record in MongoDB (similar to SQL's EXISTS function), use findOne() method. This returns the first matching document if it exists, or null if no document matches the query criteria. Syntax db.collection.findOne({ field: "value" }) Sample Data db.existsAlternateDemo.insertMany([ { "StudentName": "Chris" }, { "StudentName": "Chris", "StudentAge": 21 }, { "StudentName": "Chris", "StudentAge": 22, "StudentCountryName": "US" } ]); { "acknowledged": true, "insertedIds": [ ...
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