Server Side Programming Articles - Page 1393 of 2650

Suppose we have a list of numbers called nums, The width of a sequence of numbers as the difference between the maximum and minimum number in the sequence. We have to find the sum of widths of all subsequences of nums. If the answer is very large then mod the result by 10^9+7.So, if the input is like nums = [7, 4, 9], then the output will be 15, as we have the subsequences like: [7], [4], [9], [7, 4], [7, 9], [4, 9], [7, 4, 9] and So the widths are 0, 0, 0, 3, 2, 5, 5, so ... Read More

Suppose we have a list of numbers called nums and we can delete at most one element in the list. We have to find the maximum number of sublists that contain both the maximum and minimum values of the resulting list.So, if the input is like nums = [3, 2, 6, 2, 4, 10], then the output will be 8, as if we remove 10 we will get [3, 2, 6, 2, 4] and there are eight sublists where it contains both the max and the min −[2, 6][6, 2][2, 6, 2][3, 2, 6][6, 2, 4][2, 6, 2, 4][3, 2, ... Read More

Suppose we have a list of numbers called nums and another value pos. We have to find a sublist A of nums that includes the index pos such that (minimum of A) * (size of A) is maximized then return the value.So, if the input is like nums = [-2, 2, 5, 4] pos = 3, then the output will be 8, as the best sublist is [5, 4], because (5, 4) = 4 and its size is 2 we have 4 * 2 = 8.To solve this, we will follow these steps −ans := A[pos], m := A[pos]i := ... Read More

Suppose we have a string s, this is encoding a longer string. s is represented as the concatenation of n(t), n(t) represents the concatenation of t, n times, and t is either a regular string or it is another encoded string recursively. We have to find the decoded version of s.So, if the input is like s = "3(pi)2(3(am))0(f)1(u)", then the output will be "pipipiamamamamamamu"To solve this, we will follow these steps −i := 0Define a function parse() . This will takeans := a new listwhile i < size of s and s[i] is not same as ")", doif s[i] ... Read More

Suppose we have a 2d matrix, we have to find the largest k × k submatrix where all of its elements are containing the same value, then find the value of k.So, if the input is like1183155525554555then the output will be 3, as there is a 3 × 3 square matrix of value 5.To solve this, we will follow these steps −n := row count of matrixm := column count of matrixDefine one 2D array dp of size (n x m) and fill with 1ret := 1for initialize i := n - 1, when i >= 0, update (decrease i ... Read More

Suppose we have a lowercase string s, we have to split it into as few strings as possible such that each string is a palindrome and then find the number of strings.So, if the input is like s = "levelracecar", then the output will be 2, as there are two palindromes "level" and "racecar".To solve this, we will follow these steps −n := size of ADefine an array result of size (n + 1)result[n] := -1for initialize i := n - 1, when i >= 0, update (decrease i by 1), do −result[i] := n - i - 1for initialize ... Read More

Suppose we have a list of numbers called nums and another value k. We can split the list into k non-empty sublists. We have to find the minimum largest sum of the k sublists.So, if the input is like nums = [2, 4, 3, 5, 12] k = 2, then the output will be 14, as we can split the list like: [2, 4, 3, 5] and [12].To solve this, we will follow these steps −Define a function ok(), this will take array v, k, x,cnt := 0, sum := 0for each element i in v −if sum + i > x, then −sum := i(increase cnt by 1)Otherwisesum := sum + ireturn true when cnt

Suppose we have a list of numbers called heights that represents the height of plants and we have another list of values called costs that represents the price needed to increase height of a plant by one. We have to find the smallest cost to make each height in the heights list different from adjacent heights.So, if the input is like heights = [3, 2, 2] costs = [2, 5, 3], then the output will be 3, as we can increase the last height by 1, which costs 3.To solve this, we will follow these steps −Define a function dp() ... Read More

Suppose we have a binary matrix. Here 0 signifies an empty cell, and a 1 signifies a cell with a person. The distance between two cells is the maximum value between the difference in x coordinates and the difference in y coordinates. Now matrix is considered safe with a factor k if there is an empty square such that the distance from the cell to each person in the matrix, and each side of the matrix is all greater or equal to k. We have to find the maximum value of factor k for which we can be safe.So, if ... Read More

Suppose we have a list of numbers called nums, and an another input called target, we have to find the size of the shortest sublist such that its sum value is same as target or larger. If there is no such sublist then return -1.So, if the input is like nums = [2, 11, -4, 17, 4] target = 19, then the output will be 2, as we can select [17, 4] to get sum of at least 19.To solve this, we will follow these steps −ps := a list with only one element 0for each num in nums, doinsert ... Read More