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There should be sequence of N 0’s and M 1’s such that the sequence so formed shouldn’t contain two consecutive 0’s with three consecutive 1’s.Input − N=5 M=9Output − 1 1 0 1 1 0 1 1 0 1 0 1 0 1Note − To make the above sequence, the statement (m < n-1) || m >= 2 * (n + 1) should be false if it is true than we can’t make the above sequence.It is advisable to first go through question logic and try yourself instead of jumping to the solution directly given below.AlgorithmSTART Step 1 -> take values in ... Read More
Print the given numeric value as words. It’s easy to do with switch using cases from 0-9 but challenge is without using them.Input − N=900Output − NINE ZERO ZEROIt is possible by creating array of pointers that contains 0-9 in words.AlgorithmSTART Step 1 -> declare int variables num, i and array of pointer char *alpha with values {"ZERO", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE"} Step 2 -> declare char array str[20] Step 3 -> call function itoa with parameters num, str, 10 Step 4 -> Loop For i=0 and str[i]!=’\o’ and i++ Print alpha[str[i] - '0'] ... Read More
Input number N such that 1/N will return the output generated as decimal specified till the limit.It is easy with Floating Point numbers but the challenge is without using them.Input − n=5 k=5Output − 20000It means if n=5 and k=5 than after dividing 1/5 the output should be displayed till 5 decimal points.AlgorithmStart Step 1 -> Declare int variable n to 9 and k to 7 and remain to 1 and i Step 2-> Loop for i to 0 and i end Loop For StopExample#include int main() { int n = 9, k = 7, remain=1, i ; // taking n ... Read More
Input number N and fetch the unit digit of a given number and display the multiples of that number.Input − N=326Output − unit digit is 6 and its multiples are 2 and 3Note − Unit digit of any number can be fetched by calculating the %10 with that numberFor example − if your’re given with a number N and you need to find its unit digit thatyou can use N%10 it will return you unit digit of number NALGORITHMSTART Step 1 -> Declare start variables num, num2 and i Step 2 -> input number num Step 3 -> store num%10 in num2 ... Read More
String is a sequence of characters. In C++ programming language, The strings can be defined in two ways −C style strings: treats the string as a character array.String Class in C++The string class can be used in a C++ program from the library ‘string’. It stores the string as a character array in the memory but shows it as a string object to the user. In C++ there are many methods that support the C++ string class and help in the proper function of the object and increase the efficiency of the code.ExampleSome common string application are found where string ... Read More
Fork() bomb is a Dos (Denial Of Service) attack against the linux based system. This calls the Fork() system infinite number of times that fills the memory of the program and intends to harm the system.Bash script for fork bomb:(){ :|: & };:The code explained as :( ) is function definition, { } defines the body of the loop. :|:& create a memory location and does not allow it to get deallocated. This program call itself multiple number of time again and again. Thus calling infinite calls.C Fork bomb is also the same type of Dos but it can be ... Read More
Counting the number of trailing zeroes in a factorial number is done by counting the number of 2s and 5s in the factors of the number. Because 2*5 gives 10 which is a trailing 0 in the factorial of a number.ExampleFactorial of 7 = 5040, the number of trailing 0’s is 1.Based on our logic 7! = 2*3*4*5*6*7, it has 3 2s and 1 5s so the number of trailing 0’s is 1.#include using namespace std; int main() { int n = 45; int count = 0; for (int i = 5; n / i >= 1; i *= 5) count += n / i; cout
The sum of squares of the first n natural numbers is found by adding up all the squares.Input - 5Output - 55Explanation - 12 + 22 + 32 + 42 + 52There are two methods to find the Sum of squares of first n natural numbers −Using Loops − the code loops through the digits until n and find their square, then add this to a sum variable that outputs the sum.Example#include using namespace std; int main() { int n = 5; int sum = 0; for (int i = 1; i >= n; i++) sum += (i * i); cout
Smallest K digit number that divisible by X is found using the formula by checking divisible by X. The formula works in the following way −Compute minimum K digit number [min] for example: 10/100/1000 etc.Now find if min is divisible by X. if yes, then this is the answer.If not, then min+X - ([min+X]%k) is the answer.Example#include #include using namespace std; int main() { int X = 83; int K = 5; cout
Power function is calculated using the times multiple i.e. 5n is 5*5*5… n times. For this function, to work properly without using multiplication(*) and division(/) operators we will use nested loops that add the numbers n number of time.Example#include using namespace std; int main() { int a= 4 , b = 2; if (b == 0) cout