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C Program for Print individual digits as words without using if or switch.
Print the given numeric value as words. It’s easy to do with switch using cases from 0-9 but challenge is without using them.
Input − N=900
Output − NINE ZERO ZERO
It is possible by creating array of pointers that contains 0-9 in words.
Algorithm
START
Step 1 -> declare int variables num, i and array of pointer char *alpha with values {"ZERO", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE"}
Step 2 -> declare char array str[20]
Step 3 -> call function itoa with parameters num,str,10
Step 4 -> Loop For i=0 and str[i]!=’\o’ and i++
Print alpha[str[i] - '0']
Step 5 -> End Loop
STOPExample
#include<stdio.h>
#include<stdlib.h>
int main() {
int num, i;
num=900; //lets take numeric value
char *alpha[11] = {"ZERO", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE"};
char str[20];
itoa(num, str, 10); //this function will convert integer to alphabet
for(i=0; str[i] != '\0'; i++)
printf("%s ", alpha[str[i] - '0']);
return 0;
}Output
If we run above program then it will generate following output
Enter an integer 900 NINE ZERO ZERO
Updated on: 08-Aug-2019
205 Views
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