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A singly linked list is a data structure in which an element has two parts one is the value and other is the link to the next element. So to find the sum of all elements of the singly linked list, we have to navigate to each node of the linked list and add the element's value to a sum variable.For exampleSuppose we have a linked list: 2 -> 27 -> 32 -> 1 -> 5 sum = 2 + 27 + 32 + 1 + 5 = 67.This can be done by using two methods :Method 1 - Using a ... Read More
To find the sum of the given series, we will analyze the series and try to get some traits that show it is known series or at least is a combination of 2 - 3 series. the given series is 5, 12, 23, 38…We have to find the sum of the series for any value of nFor exampleFor n = 3 Sum = 40.On analyzing the given series, you will find that this series is Quadratic series. In quadratic series, the difference of the numbers is in an arithmetic progression( increase by definite number)So we can directly use the formula ... Read More
To find the sum of this series, we will first analyze this series.The series is:The given series is 2, 10, 30, 68…For exampleFor n = 6 Sum = 464On analysis of the given series, you will see that the series is the addition of two series first one is the series of n natural numbers and the second is the cube of n natural numbers this means the series can be split as:2, 10 , 30 ,68 = (1+13) , (2+23), (3 + 33), ( 4 + 43)so we can write the sum of the series as :sum = 2 ... Read More
To find the sum of this series, we will first analyze this series.The series is: 2,6,12,20,30…ExampleFor n = 6 Sum = 112 On analysis, (1+1),(2+4),(3+9),(4+16)... (1+12), (2+22), (3+32), (4+42), can be divided into two series i.e. s1:1,2,3,4,5… andS2: 12,2,32,....Find the sum of first and second using mathematical formulaSum1 = 1+2+3+4… , sum1 = n*(n+1)/2 Sum2 = 12+22+32+42… , sum1 = n*(n+1)*(2*n +1)/6Example#include int main() { int n = 3; int sum = ((n*(n+1))/2)+((n*(n+1)*(2*n+1))/6); printf("the sum series till %d is %d", n,sum); return 0; }OutputThe sum of series till 3 is 20
The HTML DOM input Password autofocus property is associated with the HTML element’s autofocus attribute. This property is used for setting or returning if the input password field should be automatically focused when the page loads or not.SyntaxFollowing is the syntax to −Set the autofocus property −passwordObject.autofocus = true|falseHere, true represents that the password field should get focus and false represents otherwise. It is set to false by default.ExampleLet us look at an example for the Input Password autofocus property − Input password autofocus property Password: CHECK FOCUS function FocusVal() { ... Read More
C++ Internals means how the working of C++ compiler compiling the .cpp code and giving us the output. C++ is a popular programming language mostly used for writing system software. It is an extension of the C programming language. C is a compiled language. The C++ compiler compiles C++ code to an object or executable file is generated. The executable or the binary files contains machine executable instructions and some metadata of the machine instructions.A typical way of compiling a C++ program is to run the compiler on C++ code. The compiler will generate machine instructions which are set of ... Read More
Simple Interest is the product of principal amount, rate of interest and the time duration (in years) by 100.Example,Input − p=5, r=4, t=5Output − 1Explanation: Simple Interest = (Principal Amount * Rate of Interest * Number of years) / 100SI= 5*4*5/100 = 1Example#include #include using namespace std; int main() { //principle amount float p = 5; //time float r = 4; //rate in years float t = 5; // Simple interest float SI = 0; SI =(p * t * r) / 100; printf("Simple Interest = %f ",SI); return 0; }OutputSimple Interest = 1.0000
To find the area of leaf inside a square, we need to split it into parts and find the area of parts and then add the areas to find the area of leaf.To calculate the area we are splitting the leaf into two parts.To find the area of 1st part AECA, we will find the area of quad circle AECDA and subtract the area of triangle ACDA from it.area of a Quadrant = 1⁄4 *(π*r2) whereπ = 22/7 or 3.141.area of a right angle triangle= 1⁄2*B*H = ½ a2Example#include #define PI 3.14159265 int main() { float a = 12.3; ... Read More
To reach on a conclusion on quantified statements, there are four rules of inference which are collectively called as Inference Theory of the Predicate Calculus.Table of Rules of InferenceRule of InferenceName$$\begin{matrix} \forall x P(x) \ \hline \therefore P(y) \end{matrix}$$Rule US: Universal Specification$$\begin{matrix} P(c) \text { for any c} \ \hline \therefore \forall x P(x) \end{matrix}$$Rule UG: Universal Generalization$$\begin{matrix} \exists x P(x) \ \hline \therefore P(c) \text { for any c} \ \end{matrix}$$Rule ES: Existential Specification$$\begin{matrix} P(c) \text { for any c} \ \therefore \exists x P(x) \end{matrix}$$Rule EG: Existential GeneralizationRule US: Universal Specification - From $(x)P(x)$, one can conclude $P(y)$.Rule ... Read More
Given, A square that is inscribed within a circle that is inscribed in a regular hexagon and we need to find the area of the square, for that we need to find the relation of the side of square and the side of the hexagon.The mathematical formula for the radius of circle inscribed within the hexagon is, r=A√3/2Since, the diagonal of square is equal to diameter of the circle, so the relation between the radius and side is, a=√rBased on the side of hexagon, a = √3A/√2So, Area of the Square, Area=a2 = (√3A/√2)2Example#include #include int main() { ... Read More