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The HTML DOM Input Text pattern property is used for setting or returning the pattern attribute of an input text field. It checks the text against a regular expression specified by the pattern property.SyntaxFollowing is the syntax for −Setting the pattern property −textObject.pattern = regexpHere, regexp is a regular expression against which the text field is checked.ExampleLet us look at an example for the text pattern property − Input Text pattern property The username can either be of three numeric characters or 6 alphabet characters from a to g USERNAME: GET PATTERN ... Read More
For this problem, to add elements of two given arrays we have some constraints based on which the added value will get changed. the sum of two given arrays a[] & b[] is stored into to third array c[]in such a way that they gave the some of the elements in single digit. and if the number of digits of the sum is greater than 1, then the element of the third array will split into two single-digit elements. For example, if the sum occurs to be 27, the third array with store it as 2, 7.Input: a[] = {1, ... Read More
Permutations, nPr can also be represented as P(n,r) is a mathematical formula to find the number of permutations. The formula of P(n, r) is n! / (n – r)!.The number of permutations on a set of n elements is given by n! where “!” represents factorial.Input:n=5;r=4; Output:120ExplanationP(5, 4) = 5! / (5-4)! => 120 / 1 = 120 5!=1*2*3*4*5*=120Example#include using namespace std; long int fact(int x) { int i, f=1; for(i=2; i
Convert an integer from decimal number system (base-10) to binary number system (base-2). Size of an integer is assumed to be 32 bits, need you to divide the number by the base. It is used by the computer to change integer values to bytes that are a computer.Input:10 Output:1010ExplanationIf the Decimal number is 10When 10 is divided by 2 remainders is zero. Therefore, 0.Divide 10 by 2. New number is 10/2 = 5.when 5 is divided by 2 Remainder is 1. Therefore 1.Divide 5 by 2. New number is 5/2 = 2.when 2 is divided by 2 Remainder is ... Read More
This program takes the 3 numbers and finds the biggest among all. For this, we will compare the numbers with each other and find out which is the largestInput: a=2,b=4,c=7 Output:7 Largest NumberExplanationThis program uses only if statement to find the largest number.Example#include using namespace std; int main() { int a,b,c; a=2,b=4,c=7; if(a>b) { if(a>c) { printf("%d Largest Number ",a); } else { printf("%d Largest Number ",c); } } else { if(b>c) { printf("%d Largest Number ",b); } else { printf("%d Largest Number ",c); } } return 0; }
A number which is greater than 0 is positive and less than 0 are negative. The concept of positive and negative is very important in number theory and programming also. Calculations rely on this concept only.Input: 0 Output:0 is zeroExplanationUsing conditional statement check the number with 0 weather it is greater than 0 or smaller than 0.Example#include using namespace std; int main() { int n=0; if(n>0) { printf("%d is positive",n); } else if(n
A number is called an Armstrong number if the sum of cubes of digits of the number is equal to the number itself. It is a mathematical concept usually used in programming to build basic logic of the programmerInput:370 Output:370 is an Armstrong NumberExplanation370 = 3*3*3 + 7*7*7 + 0*0*0 = 27 + 343 + 0 = 370Exampleinclude using namespace std; int main() { int n, num, rem, sum = 0; cin >> n; num = n; while(num != 0) { digit = num % 10; sum += digit * digit * digit; num /= 10; } if(sum == n) printf("%d is an Armstrong number.", n ); else printf("%d is not an Armstrong number.",n); return 0; }
Sum of all Array elements means add all array Elements. Suppose we have 5 Elements in array and we want to find there sum.arr[0]=1 arr[1]=2 arr[2]=3 arr[3]=4 arr[4]=5Sum off all above elements arearr[0]+arr[1]+arr[2]+arr[3]+ arr[4]=1+2+3+4+5=15Input:1,2,3,4,5 Output:15ExplanationUsing For loop to get to the every index element and taking sum of themarr[0]+arr[1]+arr[2]+arr[3]+ arr[4]=1+2+3+4+5=15Example#include using namespace std; int main() { int i,n,sum=0; int arr[]={1,2,3,4,5}; n=5; for(i=0;i
Given a number, find the difference between sum of odd digits and sum of even digits. Which means we will be count all even digits and all odd digits and the subtracting their sums.SampleInput:12345 Output:3Explanationthe odd digits is 2+4=6 the even digits is 1+3+5=9 odd-even=9-6=3Taking every digit out of number and checking whether the digit is even or odd if even then add it to even sum if not then to odd sum and then take difference of them.Example#include using namespace std; int main() { int n, r=0; int diff =0; int even=0; int odd=0; ... Read More
The cube sum of first n natural numbers is the program to add cubes of all natural numbers up to n. It is sum of series 1^3 + 2^3 + …. + n^3 that is sum of cube of n natural numbers.Input:6 Output:441Explanation1^3 + 2^3 + 3^3 + 4^3 + 5^3 + 63 = 441Using For loop to increase the no. and cubing it and taking sum of them.Example#include using namespace std; int main() { int n = 6; int sum = 0; for (int i = 1; i