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There are different ways to iterate through a tuple object. The for statement in Python has a variant which traverses a tuple till it is exhausted. It is equivalent to foreach statement in Java. Its syntax is −for var in tuple: stmt1 stmt2ExampleFollowing script will print all items in the listT = (10, 20, 30, 40, 50) for var in T: print (T.index(var), var)OutputThe output generated is −0 10 1 20 2 30 3 40 4 50Another approach is to iterate over range upto length of tuple, and use it as index of item in tupleExamplefor var in range(len(T)): ... Read More
The following code matches tab and newline but not space from given string using regex.Exampleimport re print re.findall(r"[\t]","""I find Tutorialspoint useful""")OutputThis gives the output['']
The following code removes tabs and newlines from given stringExampleimport re print re.sub(r"\s+", " ", """I find Tutorialspoint helpful""")OutputThis gives outputI find Tutorialspoint helpful
To convert a stream to an Array in Java -Collect the stream to a list using the Collect interface and the Collectors class.Now convert the list to an array using the toArray() method.ExampleLive Demoimport java.util.Arrays; import java.util.List; import java.util.stream.Collectors; import java.util.stream.Stream; public class J8StreamToArray { public static void main(String args[]) { String[] myArray = { "JavaFX", "OpenCV", "WebGL", "HBase" }; Stream stream = Stream.of(myArray); List list = stream.collect(Collectors.toList()); String[] str = list.toArray(new String[0]); System.out.println(Arrays.toString(str)); } }Output[JavaFX, OpenCV, WebGL, HBase]
The FileInputStream class contains a method read(), this method accepts a byte array as a parameter and it reads the data of the file input stream to given byte array.Exampleimport java.io.File; import java.io.FileInputStream; public class FileToByteArray { public static void main(String args[]) throws Exception { File file = new File("HelloWorld"); FileInputStream fis = new FileInputStream(file); byte[] bytesArray = new byte[(int)file.length()]; fis.read(bytesArray); String s = new String(bytesArray); System.out.println(s); } }Output//Class declaration public class SampleProgram { /* This is my ... Read More
Apache commons provides a library named org.apache.commons.lang3 and, following is the maven dependency to add library to your project. org.apache.commons commons-lang3 3.0 This package provides a class named ArrayUtils. You can add an element at a particular position in an array using the add() method of this class.Exampleimport java.util.Arrays; import org.apache.commons.lang3.ArrayUtils; public class AddingElementToMidPoint { public static void main(String args[]) { int[] myArray = {23, 93, 30, 56, 92, 39}; int eleToAdd = 40; int position= myArray.length/2; int [] result = ArrayUtils.add(myArray, position, eleToAdd); System.out.println(Arrays.toString(result)); } }Output[23, 93, 30, 40, 56, 92, 39]
We can compare given strings using the following codeExampleimport re s1 = 'Pink Forest' s2 = 'Pink Forrest' if bool(re.search(s1,s2))==True: print 'Strings match' else: print 'Strings do not match'OutputThis gives the outputStrings do not match
Suppose we have three integers a, b and c. Suppose in an infinite sequence, a is the first term, and c is a common difference. We have to check whether b is present in the sequence or not. Suppose the values are like a = 1, b = 7 and c = 3, Then the sequence will be 1, 4, 7, 10, …, so 7 is present in the sequence, so the output will be ‘yes’.To solve this problem, we have to follow these two steps −When c = 0, and a = b, then print yes, and if a ... Read More
In this tutorial, we will be discussing a program to interchange the diagonals of a given matrix.For this, we will be given with a square matrix of the order n*n. Our task is to interchange the elements in the two diagonals of the matrix and then return the new matrix.Example Live Demo#include using namespace std; #define N 3 //interchanging the two diagonals void int_diag(int array[][N]){ for (int i = 0; i < N; ++i) if (i != N / 2) swap(array[i][i], array[i][N - i - 1]); for (int i = 0; i < N; ++i){ ... Read More
Consider we have an expression exp, and we have to check whether the exp has a duplicate set of parentheses around it or not. An expression will have duplicate parentheses if one sub-expression will be surrounded by more than one parentheses set. For example, if the expression is like −(5+((7−3)))Here the sub-expression (7 – 3) is surrounded by two parentheses pair, so these are duplicate parentheses.To solve this problem, we will use stacks. We will iterate through each character in the exp, and if the character is opening parentheses ‘(’, or any of the operator or operand, then push it ... Read More