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Articles on Trending Technologies
Technical articles with clear explanations and examples
Construct BST from given preorder traversal - Set 1 in C++
Suppose we have one pre order traversal. From this traversal. we have to generate the tree So if the traversal is like [10, 5, 1, 7, 40, 50], then the tree will be like −To solve this, we will use this trick. The trick is to set a range {min… max} for each node. At first we will initialize the range as {INT_MIN… INT_MAX}. The first node will definitely be in range, so after that we will create root node. To construct the left subtree, set the range as {INT_MIN… root->data}. If a values is in the range {INT_MIN… root->data}, ...
Read MoreConstruct a Turing Machine for language L = {ww | w ∈ {0,1}}
Here we will see how to make a Turing machine for language L = {WW |W belongs to {0, 1}}. So this represents a kind of language where we will use only two characters 0s and 1s. The w is a string. So if w = 10110, so the Turing machine will accept the string z = 1011010110.To solve this, we will use this approach. The first thing is to find the midpoint of the string, we will convert a 0 to x and 1 to y. After continuously doing it a point is reached when all 0’s and 1’s ...
Read MoreConstruct a Turing Machine for language L = {0n1n2n | n≥1}
Here we will see how to make a Turing machine for language L = {0n1n2n | n ≥ n}. So this represents a kind of language where we will use only three characters 0s, 1s and 2s. The w is a string. So if w = 000111222, The Turing machine will accept it.To solve this, we will use this approach. First replace one 0 from front by x, then keep moving right till we get one 1 and replace this 1 by y. Again, keep moving right till we get one 2, replace it by z and move left. Now ...
Read MoreConstruct a Turing machine for L = {aibjck | i*j = k; i, j, k ≥ 1}
Here we will see how to make a Turing machine for language L = {AiBjCk | i * j = k; i, j, k ≥ 1}. So this represents a kind of language where we will use only three characters A, B and C. The w is a string. So if w = AABBBBCCCCCCCC, The Turing machine will accept it.To solve this, we will use this approach.First replace an A with x and move right. Then skip all the A’s and move rightWhen the head reach to the first B then replace one B with y, then move right skipping ...
Read MoreTop Reasons to Learn C++
Here we will see some good reasons behind taking the language C++ as our favorite programming language. We know that C++ is one of the most popular object oriented programming language. These are the reasons behind taking the C++ into consideration.C++ Popularity and High salary −C++ is one of the most popular language in the world. It is used nearly 4.4 million developers worldwide. The C++ developers hold highest paying jobs in the industry with an average base pay of $100000 per year.C++ has abundant library supportv −C++ has Standard Template Library (STL). This helps to write code compactly and ...
Read MorePrint all ways to break a string in bracket form in C++
In this problem, we are given a string and we have to break it into substrings and print them enclosing brackets.Let’s take a few examples to understand the problem better, Input : wxyz Output : (w) (x) (y) (z) (w) (x) (yz) (w) (xy) (z) (w) (xyz) (wx) (y) (z) (wx) (yz) (wxy) (z) (wxyz)Explanation − We will break the string into all possible substrings. And enclose each substring with brackets.Now, since we have understood the problem, let’s create a solution to the problem.Here, we will use recursion to solve the problem. ...
Read MorePrint BST keys in the given range in C++
In this problem, we are given two nodes of a binary search tree. And we have to print all the values in the range of k1 to k2 that occur in the tree. That is we have to print all the values that are greater than k1 and smaller than k2. And we have to print all these keys in increasing order of their values.Binary Search Tree is a tree which follows these 3 properties −The left subtree has nodes with values lesser than the node’s value.The right subtree has a node with values greater than the node’s value.A subtree’s ...
Read MorePrint common nodes on path from root (or common ancestors) in C++
In this problem, we are given a binary tree and two nodes of the binary tree are defined. And we have to print all the common ancestors of the node i.e. common nodes that occur in the path from traversal from root to the node.Binary Tree is a special tree whose every node has at max two child nodes. So, every node is either a leaf node or has one or two child nodes.Example, Ancestor node is a node that is connected to lower-level nodes in a tree.The common ancestor node of two nodes is a node that is an ...
Read MorePrint cousins of a given node in Binary Treein C++
Binary Tree is a special tree whose every node has at max two child nodes. So, every node is either a leaf node or has one or two child nodes.Example, In this problem, we are given a binary tree and we have a node of the tree and we have to find the cousin nodes of the node. No sibling nodes are to be printed for the binary tree.Let’s take an example, For the above binary tree, the cousin node is 5.To make the concept more clear let’s describe cousin node. In a binary tree, two nodes are said to ...
Read MoreMulti-Way Trees
A multiway tree is defined as a tree that can have more than two children. If a multiway tree can have maximum m children, then this tree is called as multiway tree of order m (or an m-way tree).As with the other trees that have been studied, the nodes in an m-way tree will be made up of m-1 key fields and pointers to children.multiway tree of order 5To make the processing of m-way trees easier some type of constraint or order will be imposed on the keys within each node, resulting in a multiway search tree of order m ...
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