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A loop statement allows us to execute a statement or a group of statements multiple times. The following are the loops supported in C# −Sr.NoLoop Type & Description1while loopIt repeats a statement or a group of statements while a given condition is true. It tests the condition before executing the loop body.2for loopIt executes a sequence of statements multiple times and abbreviates the code that manages the loop variable.3do...while loopIt is similar to a while statement, except that it tests the condition at the end of the loop bodyWith C#, you can also use foreach loop as shown below −Example Live ... Read More
You can try to run the following code to rotate div with matrix transforms using CSS:ExampleLive Demo div { width: 300px; height: 100px; background-color: pink; border: 1px solid black; } div#myDiv1 { /* IE 9 */ -ms-transform: matrix(1, -0.3, 0, 1, 0, 0); /* Safari */ -webkit-transform: matrix(1, -0.3, 0, 1, 0, 0); /* Standard syntax */ transform: matrix(1, -0.3, 0, 1, 0, 0); } Welcome to my website. Welcome to my website. Output
The sizeof() datatype returns the size of a data type. Let’s say you need to find the size of int datatype −sizeof(int);For double datatype −sizeof(double);Let us see the complete example to find the size of various datatypes −Example Live Demousing System; namespace Demo { class Program { static void Main(string[] args) { Console.WriteLine("The size of long is {0}", sizeof(long)); Console.WriteLine("The size of double is {0}", sizeof(double)); Console.ReadLine(); } } }OutputThe size of long is 8 The size of double is 8
To calculate the power exponent value, use the Math.pow() method.Here, n is the number and p is the power −double res = Math.Pow(n, p);The following is the complete code −Example Live Demousing System; class Program { static void Main() { double n, p; n = 7; p = 3; Console.WriteLine("Exponent Power= "+n); double res = Math.Pow(n, p); Console.WriteLine("Result= {0}", res); Console.ReadLine(); } }OutputExponent Power= 7 Result= 343
To find Fibonaccli series, firsty set the first two number in the series as 0 and 1.int val1 = 0, val2 = 1, vNow loop through 2 to n and find the fibonai series. Every number in the series is the sum of the last 2 elements −for(i=2;i
Use the new keyword to create an instance of the array −int [] a = new int[5];The new operator is used to create an object or instantiate an object. Here in the example, an object is created for the class using the new −Example Live Demousing System; namespace CalculatorApplication { class NumberManipulator { public void swap(int x, int y) { int temp; temp = x; /* save the value of x */ x = y; /* put y into x */ ... Read More
The Values property gets an ICollection containing the values in the Hashtable.Declare Hashtable collection −Hashtable ht = new Hashtable();Now add valuesht.Add("One", "Henry"); ht.Add("Two", "Kevin"); ht.Add("Three", "David");To display values from Hashtable, the following is the code −Example Live Demousing System; using System.Collections; namespace Demo { class Program { static void Main(string[] args) { Hashtable ht = new Hashtable(); ht.Add("One", "Henry"); ht.Add("Two", "Kevin"); ht.Add("Three", "David"); // Displaying values foreach (string value in ht.Values) { Console.WriteLine(value); } Console.ReadKey(); } } }OutputDavid Henry Kevin
Firstly, declare the SortedList class −SortedList list = new SortedList();Now add the values −list.Add("S1", "Wallets"); list.Add("S2", "Sunglasses"); list.Add("S3", "Backpacks");The following is the code to work with Values property of SortedList class −Example Live Demousing System; using System.Collections; namespace Demo { class Program { static void Main(string[] args) { SortedList list = new SortedList(); list.Add("S1", "Wallets"); list.Add("S2", "Sunglasses"); list.Add("S3", "Backpacks"); foreach (string value in list.Values) { Console.WriteLine(value); } } } }OutputWallets Sunglasses Backpacks
For power of 3, se the power as 3 and apply a recursive code like the following snippet −if (p!=0) { return (n * power(n, p - 1)); }Let’s say the number is 5, then the iterations would be −power(5, 3 - 1)); // 25 power (5,2-1): // 5The above would return5*25 i.e 125 as shown below −Example Live Demousing System; using System.IO; public class Demo { public static void Main(string[] args) { int n = 5; int p = 3; long res; res = power(n, p); Console.WriteLine(res); } static long power (int n, int p) { if (p!=0) { return (n * power(n, p - 1)); } return 1; } }Output125
Suppose if we are trying to add the numbers having non-numeric text before them, then MySQL simply evaluate the value of such number as 0. Following example will exhibit this −Examplemysql> Select 'Kg 1525' + 'Oz 200'As Total; +-------+ | Total | +-------+ | 0 | +-------+ 1 row in set, 2 warnings (0.00 sec) mysql> Select 'Kg 1525' + '200'As Total; +-------+ | Total | +-------+ | 200 | +-------+ 1 row in set, 1 warning (0.00 sec)