Find the Smallest Element Among Three Elements in C++

Ayush Gupta
Updated on 09-Jul-2020 08:54:23

2K+ Views

In this tutorial, we will be discussing a program to find the smallest element among the provided three elements.We will be provided with three elements/ integers and our task is to compare them and find the smallest element/ integer among them.Example#include using namespace std; int main() {    int a = 45, b = 72, c = 10;    if (a

Find Sum of Each Row and Column of a Matrix in C++

Ayush Gupta
Updated on 09-Jul-2020 08:53:58

2K+ Views

In this tutorial, we will be discussing a program to find the sum of each row and each column for a given matrix.For this, we will be given with a say A*B matrix. Our task is to traverse through all the elements of the matrix and find the sum of each row and each column of the matrix.Example#include using namespace std; #define m 7 #define n 6 //calculating sum of each row void calc_rsum(int arr[m][n]){    int i,j,sum = 0;    for (i = 0; i < 4; ++i) {       for (j = 0; j < 4; ++j) {          sum = sum + arr[i][j];       }       cout

Find the Sum of the Series 1 + 2 + 3 + 4 + 5 + ... + n in C++

Ayush Gupta
Updated on 09-Jul-2020 08:53:33

397 Views

In this tutorial, we will be discussing a program to find the sum of the given series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n).For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.Example#include using namespace std; //calculating the sum of the series int calc_sum(int n) {    int i;    int sum = 0;    for (i = 1; i

Find the Sum of the Series 1^a + 2^a^2 + 3^a^3 + ... + n^a^n in C++

Ayush Gupta
Updated on 09-Jul-2020 08:53:06

163 Views

In this tutorial, we will be discussing a program to find the sum of the given series (1/a + 2/a^2 + 3/a^3 + … + n/a^n).For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.Example#include #include using namespace std; //calculating the sum of the series float calc_sum(int a, int n) {    int i;    float sum = 0;    for (i = 1; i

C++ Program to Find the Sum of the Series 1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + ... + n

Ayush Gupta
Updated on 09-Jul-2020 08:52:42

584 Views

In this tutorial, we will be discussing a program to find the sum of the given series 1/1! + 2/2! + 3/3! + 4/4! +…….+ n/n!.For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.Example#include using namespace std; //calculating the sum of the series double calc_sum(int n) {    int i;    double sum = 0, fact=1;    for (i = 1; i

Find the Sum of the Series 2+3, 4+5, 7+5 Up to N Terms in C++

Ayush Gupta
Updated on 09-Jul-2020 08:52:15

255 Views

In this tutorial, we will be discussing a program to find the sum of the given series 23+ 45+ 75+….. upto N terms.For this, we will be given with the value of N and our task is to add up every term starting from the first one to find the sum of the given series.After solving this, we get the formula for the sum of the series;Sn = (2n(n+1)(4n+17)+54n)/6Example#include using namespace std; //calculating the sum of the series int calc_sum(int N) {    int i;    int sum = (2 * N * (N + 1) * (4 * ... Read More

Find the Sum of the Series 1 + 1/2 + 2 + 1/3 + 3 + ... + 1/n in C++

Ayush Gupta
Updated on 09-Jul-2020 08:51:51

851 Views

In this tutorial, we will be discussing a program to find the sum of the given series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n.For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.Example#include #include using namespace std; //calculating the sum of the series double calc_sum(int n) {    int i;    double sum = 0.0, ser;    for (i = 1; i

C++ Program for Deadlock-Free Condition in Operating Systems

Sunidhi Bansal
Updated on 09-Jul-2020 08:50:06

4K+ Views

Given with the P number of processes in the memory and N number of needed resources by them to complete their execution and the task is to find the minimum number of resources R which should be allotted to the processes such that deadlock will never occur.What is a DeadlockDeadlock is situation in an operating system where multiple processes residing in the memory doesn’t able to perform their execution because the resources which are needed for program execution is being hold by another resource who is waiting for some other resource for completion.Let’s say there are two processes P1 and ... Read More

C Program for Binomial Coefficients Table

Sunidhi Bansal
Updated on 09-Jul-2020 08:48:19

8K+ Views

Given with a positive integer value let’s say ‘val’ and the task is to print the value of binomial coefficient B(n, k) where, n and k be any value between 0 to val and hence display the result.What is Binomial CoefficientBinomial coefficient (n, k) is the order of choosing ‘k’ results from the given ‘n’ possibilities. The value of binomial coefficient of positive n and k is given by$$C_k^n=\frac{n!}{(n-k)!k!}$$where, n >= kExampleInput-: B(9, 2) Output-:$$B_2^9=\frac{9!}{(9-2)!2!}$$ $$\frac{9\times 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1}{6\times 5\times 4\times 3\times 2\times 1)\times 2\times 1}=\frac{362, 880}{1440}=252$$What is Binomial Coefficient TableThe Binomial Coefficient Table is formed ... Read More

C Program for Circumference of a Parallelogram

Sunidhi Bansal
Updated on 09-Jul-2020 08:45:53

228 Views

We are given with the sides of parallelogram and the task is to generate the circumference of a parallelogram with its given sides and display the resultWhat is a Parallelogram?Parallelogram is a type of quadratic which have −Opposite sides parallelOpposite angles equalPolygon diagonals bisects each otherShown in the below figure ‘a’ and ‘b’ are the sides of a parallelogram where parallel sides are shown in the figure.Perimeter/Circumference of a parallelogram is defined as −Circumference of Parallelogram = 2(a + b)                                           ... Read More

Advertisements