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Suppose we have a string s. Here s is representing a 12-hour clock time with suffixes am or pm, we have to find its 24-hour equivalent.So, if the input is like "08:40pm", then the output will be "20:40"To solve this, we will follow these steps −hour := (convert the substring of s [from index 0 to 2] as integer) mod 12minutes := convert the substring of s [from index 3 to 5] as integerif s[5] is same as 'p', thenhour := hour + 12return the result as hour:minutesLet us see the following implementation to get better understanding −Example Live Democlass Solution: ... Read More
Suppose we have an integer n, where only 1, 2, and 3 these digits are present. We can flip one digit to a 3. Then find the maximum number we can make.So, if the input is like 11332, then the output will be 31332To solve this, we will follow these steps −li := a list by digits of nfor x in range 0 to size of li - 1, doif li[x] is not '3', thenli[x] := '3'return the number by merging digits from lireturn nLet us see the following implementation to get better understanding −Example Live Democlass Solution: def solve(self, ... Read More
Suppose we have a lowercase alphabet string s, we have to find the length of the shortest substring (minimum length is 2) such that some letter appears more than the other letters combined. If we cannot find any solution, then return -1.So, if the input is like "abbbcde", then the output will be 2, the substring "bb" has minimum length and this appears more than other letters.To solve this, we will follow these steps −Define a function ok(), this will take an array cnt, total := 0, maxVal := 0for each element it in cnt, dototal := total + itmaxVal ... Read More
Suppose we have a list of numbers. We have to define a method that can rotate a list of numbers to the left by k elements.So, if the input is like [5, 4, 7, 8, 5, 6, 8, 7, 9, 2], k = 2, then the output will be [8, 5, 6, 8, 7, 9, 2, 5, 4, 7]To solve this, we will follow these steps −Define an array retn := size of numsk := k mod nfor initialize i := k, when i < n, update (increase i by 1), do −insert nums[i] at the end of retfor initialize ... Read More
Suppose we have a list of intervals where each interval contains the [start, end] times. We have to find the minimum total size of any two non-overlapping intervals, where the size of an interval is (end - start + 1). If we cannot find such two intervals, return 0.So, if the input is like [[2, 5], [9, 10], [4, 6]], then the output will be 5 as we can pick interval [4, 6] of size 3 and [9, 10] of size 2.To solve this, we will follow these steps −ret := infn := size of vsort the array v based ... Read More
Suppose we have a string s containing only '(' and ')', we have to find the minimum number of brackets that can be inserted to make the string balanced.So, if the input is like "(()))(", then the output will be 2 as "(()))(", this can be made balanced like "((()))()".To solve this, we will follow these steps −:= 0, cnt := 0for initialize i := 0, when i < size of s, update (increase i by 1), do −if s[i] is same as '(', then −(increase o by 1)Otherwiseif o is non-zero, then −(decrease o by 1)Otherwise(increase cnt by 1)return ... Read More
Suppose we have a singly linked list node containing positive numbers. We have to find the same linked list where every node's next points to the node val nodes ahead. If we cannot find such node, next will be null.So, if the input is like [2, 3, 10, 5, 9], then the output will be [2, 3, 15, ]To solve this, we will follow these steps −Define an array vwhile node is not null, do −insert value of node into vnode := next of noderet = new list node with value 0temp = reti := 0while i < size of ... Read More
Suppose we have two binary trees called source and target; we have to check whether there is some inversion T of source such that it is a subtree of the target. So, it means there is a node in target that is identically same in values and structure as T including all of its descendants.As we know a tree is said to be an inversion of another tree if either −Both trees are emptyIts left and right children are optionally swapped and its left and right subtrees are inversions.So, if the input is like sourceTargetthen the output will be TrueTo ... Read More
Suppose we have a binary tree root; we have to count the number of nodes where its value is greater than or equal to the values of all of its descendants.So, if the input is likethen the output will be 4 as all nodes except 3, it meets the criteria.To solve this, we will follow these steps −Define a function dfs(), this will take node, if node is not null, then −return 0l := dfs(left of node)r := dfs(right of node)if val of node >= maximum of l and r, then −(increase ret by 1)x := maximum of val of ... Read More
Suppose we have a string s, we have to eliminate consecutive duplicate characters from the given string and return it. So, if a list contains consecutive repeated characters, they should be replaced with a single copy of the character. The order of the elements will be same as before.So, if the input is like "heeeeelllllllloooooo", then the output will be "helo"To solve this, we will follow these steps −ret := a blank stringfor initialize i := 0, when i < size of s, update (increase i by 1), do −if size of ret is non-zero and last element of ret ... Read More