Count Number of Triplets (a, b, c) in C++

Sunidhi Bansal
Updated on 29-Aug-2020 08:55:45

567 Views

We are given an integer n. The goal is to find triplets ( set of 3 numbers ) that satisfy the conditions −a2+b2=c21

Count Steps to Reduce N to 1 in C++

Sunidhi Bansal
Updated on 29-Aug-2020 08:51:32

393 Views

We are given a number N. The goal is to count the number of steps required to reduce the number to 1 by following rules −If the number is power of 2, reduce it to its half.Else reduce it to the N-(nearest power of 2 which is less than N).For step 1, we will check if N is power of 2, by checking if ceil(log2(N)), floor(log2(N)) return the same result. If yes then N=N/3, increment count of operation.If the result of step 1 is false then we will perform step 2 and subtract the nearest power of 2 less than ... Read More

Count Solutions of x^2 ≡ 1 (mod p) in Given Range in C++

Sunidhi Bansal
Updated on 29-Aug-2020 08:48:06

157 Views

We are given with integers x and p. The goal is to find the number of solutions of the equation −x2=1 ( mod p ) such that x lies in range [1, N].We will do this by traversing from 1 to N and take each number as x check if (x*x)%p==1. If yes then increment the count.Let’s understand with examples.Input − n=5, p=2Output − Number of Solutions − 3Explanation − Between the range 1 to 5.12=1%2=1, count=1 22=4%2=0, count=1 32=9%2=1, count=2 42=16%2=0, count=2 52=25%2=1, count=3 Total number of solutions=3.Input − n=3, p=4Output − Number of Solutions − 2Explanation − Between ... Read More

Count Right Triangles with Given Perimeter in C++

Sunidhi Bansal
Updated on 29-Aug-2020 08:44:24

351 Views

We are given a perimeter P of a triangle. Perimeter is the sum of all sides of the triangle. The goal is to find the number of right triangles that can be made which have the same perimeter.If the sides of the triangle are a, b and c. Then a + b + c = P and a2 + b2 = c2 ( pythagoras theorem for any combination of a, b, and c )We will check this by taking a from 1 to p/2 and b from a+1 to p/3. Then c = p-a-b (a+b+c=p)For all right triangles, apply Pythagoras ... Read More

Count Number of Squares in a Rectangle in C++

Sunidhi Bansal
Updated on 29-Aug-2020 08:41:48

731 Views

We are given with a rectangle of length L and breadth B, such that L>=B. The goal is to find the number of squares that a rectangle of size LXB can accommodate.Above figure shows a rectangle of size 3 X 2. It has 2, 2X2 squares and 6, 1X1 squares in it.Total squares= 6+2=8.Every rectangle of size LXB has L*B number of 1X1 squares.Biggest squares are of size BXB.For L=B=1, squares = 1.For L=B=2, squares = 1 + 4 = 5. ( 1 of 2X2, 4 of 1X1 )For L=B=3, squares = 1 + 4 + 9 = 14. ( ... Read More

Count Number of Smallest Elements in Given Range in C++

Sunidhi Bansal
Updated on 29-Aug-2020 08:37:30

303 Views

We are given an array of integers of size N. Variables L and R define a range between 1 and N. The goal is to find the number of smallest elements that lie in range L and R such that L>=1 and R

Count Number of Primes in an Array in C++

Sunidhi Bansal
Updated on 29-Aug-2020 08:33:54

10K+ Views

We are given with an array of numbers. The goal is to find the count of prime numbers in that array.A prime number is the one which is divisible by 1 and the number itself. It has only two factors. We will check if the number is prime starting from the first element till the last and increase the count of prime numbers found so far.To check if the number N is prime, check if numbers between the range [2 to N/2], fully divides N. If yes then it is non-prime. Else it is prime.Let’s understand with examples.Input − arr[]= ... Read More

Maximize Profit When Divisibility by Two Numbers in C++

Sunidhi Bansal
Updated on 29-Aug-2020 08:30:31

147 Views

We are given with five integers N, A, B, X and Y. The goal is to maximize the profit by checking that between numbers in range [ 1 to N ] , ifA number is divisible by A, then profit increases by X.A number is divisible by B then profit increases by Y.A profit can be added once only, for a particular number in range.Let’s understand with examples.Input − N=4, A=2, B=3, X=2, Y=3Output − Maximized profit is − 7Explanation −2, 4 are divisible by A ( 2 ). Profit increases from 0 to 2, then 2 to 4 ( ... Read More

Maximum Number of Partitions That Can Be Sorted Individually in C++

Sunidhi Bansal
Updated on 29-Aug-2020 08:27:47

681 Views

We are given with an array of N numbers with elements lying in range 0 and N-1. The elements are unsorted. The goal is to find the maximum number of partitions of the array which can be sorted individually and then can be concatenated to make a whole sorted array of length N.Each partition is chosen such that elements in it are unsorted. For N numbers ranging between 0 and N-1, sorted elements are at index equal to the value. Arr[i] = i.We will solve this by comparing each element by maximum value found so far on its left. When ... Read More

Save Plot as SVG Using ggplot2 in R

Nizamuddin Siddiqui
Updated on 29-Aug-2020 08:05:31

5K+ Views

   There are multiple ways to save a plot created in R. Base R provides, metafile, bitmap, and postscript options to copy and save the plots created in R but we can also save the plots created with ggplot2 as an SVG file with the help of svglite package. The ggsave function of svglite package does this job easily and we can also define the height and width of the plot inside this function.Example Live DemoInstall the svglite package −install.packages("svglite")Consider the ToothGrowth data and create a scatterplot between len and dose −head(ToothGrowth) len supp dose 1 4.2 VC ... Read More

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