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We are required to write a JavaScript function that takes in an array of intervals (start and end time like this −const arr = [ { start: '01:00', end: '04:00' }, { start: '05:00', end: '08:00' }, { start: '07:00', end: '11:00' }, { start: '09:30', end: '18:00' }, ];Our function should iterate through this array of objects and check all elements of the array against the others.If an overlapping interval is found, the iteration stops and true is returned, Otherwise false. By overlapping intervals, we mean time intervals that have some time in common.Exampleconst arr ... Read More
We are required to write a JavaScript function that takes in a string of any length. The function should then count the number of words in that string.Exampleconst str = 'THis is an example string'; const findWords = (str = '') => { if(!str.length){ return 0; }; let count = 1; for(let i = 0; i < str.length; i++){ if(str[i] === ' '){ count++; }; }; return count; }; console.log(findWords(str));OutputAnd the output in the console will be −5
The perimeter of a triangle is the sum of all three sides of the triangle. We are required to write a JavaScript function that takes in an array of numbers of at least three or more elements.Our function should pick three longest sides (largest numbers) from the array that when summed can give the maximum perimeter from the array, we need to make sure that the three picked side can make a triangle in reality. If three exists no three sides in the array that can make a valid triangle, then we have to return zero.A valid triangle is that ... Read More
We are given two strings, say s and t. String t is generated by random shuffling string s and then add one more letter at a random position.We are required to write a JavaScript function that takes both these strings and returns the letter that was added to t.For example −If the input stings are −const s = "abcd", t = "abcde";Then the output should be −const output = "e";because 'e' is the letter that was added.Exampleconst s = "abcd", t = "abcde"; const findTheDifference = (s, t) => { let a = 0, b = 0; let charCode, ... Read More
We know that natural numbers in Mathematics are the numbers starting from 1 and spanning infinitely.First 15 natural numbers are −1 2 3 4 5 6 7 8 9 10 11 12 13 14 15Therefore, the first natural digit is 1, second is 2, third is 3 and so on. But when we exceed 9, then tenth natural digit is the first digit of 10 i.e., 1 and 11th natural digit is the next i.e., 0.We are required to write a JavaScript function that takes in a number, say n, and finds and returns the nth natural digit.Exampleconst findNthDigit = ... Read More
Given a string containing just the characters '(' and ')', we find the length of the longest valid (well-formed) parentheses substring.A set of parentheses qualifies to be a well-formed parentheses, if and only if, for each opening parentheses, it contains a closing parentheses.For example −'(())()' is a well-formed parentheses '())' is not a well-formed parentheses '()()()' is a well-formed parenthesesExampleconst str = '(())()((('; const longestValidParentheses = (str = '') => { var ts = str.split(''); var stack = [], max = 0; ts.forEach((el, ind) => { ... Read More
We are required to write a JavaScript function that takes in an array of Numbers. The array of numbers can contain both positive as well as negative numbers.The purpose of our function is to find the sub array from the array (of any length), whose elements when summed gives the maximum sum. Then the function should return the sum of the elements of that subarray.For example −If the input array is −const arr = [-2, 1, -3, 4, -1, 2, 1, -5, 4];Then the output should be −const output = 6because, [4, -1, 2, 1] has the largest sum of ... Read More
We are required to write a JavaScript function that takes in two numbers say m and n. Then function should calculate and return m^n.For example − For m = 4, n = 3, thenpower(4, 3) = 4^3 = 4 * 4 * 4 = 64 power(6, 3) = 216The code for this will be the following using the power() function in JavaScript −Exampleconst power = (m, n) => { if(n < 0 && m !== 0){ return power(1/m, n*-1); }; if(n === 0){ return 1; } if(n === 1){ return m; }; if (n % 2 === 0){ const res = power(m, n / 2); return res * res; }else{ return power(m, n - 1) * m; }; }; console.log(power(4, 3)); console.log(power(6, 3));OutputAnd the output in the console will be −64 216
Suppose, we have an array of objects that contains information about some data storage devices like this −const drives = [ {size:"900GB", count:3}, {size:"900GB", count:100}, {size:"1200GB", count:5}, {size:"900GB", count:1} ];Notice like how the same size comes multiple times.We are required to write a function that takes in one such array and consolidate all repeated sizes into just one single array index and obviously adding up their counts.Exampleconst drives = [ {size:"900GB", count:3}, {size:"900GB", count:100}, {size:"1200GB", count:5}, {size:"900GB", count:1} ]; const groupDrives = (arr = []) => { const map = ... Read More
Suppose, we have two arrays of literals like this −const arr1 = ['uno', 'dos', 'tres', 'cuatro']; const arr2 = ['dos', 'cuatro'];We are required to write a JavaScript function that takes in two such arrays and delete all those elements from the first array that are also included in the second array.Therefore, for these arrays, the output should look like this −const output = ['uno', 'tres'];Exampleconst arr1 = ['uno', 'dos', 'tres', 'cuatro']; const arr2 = ['dos', 'cuatro']; const findSubtraction = (arr1 = [], arr2 = []) => { let filtered = []; filtered = arr1.filter(el => { ... Read More