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In this problem, we are given an array divisors[] consisting of N integers which are the divisors of a number Num. Our task is to find the number from its divisors.The divisor array does not include 1 and the number.Let’s take an example to understand the problem, Inputdivisors[] = {3, 25, 5, 15}Output75ExplanationThe number 75 has divisors {3, 25, 5, 15}Solution ApproachTo solve the problem, we need to find the number Num using the smallest and largest divisors of the number.Num = smallest * largestFor this, we need to sort the array divisors[] and then find the product of elements ... Read More
In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 5, 13, 25, 41, 61, …Let’s take an example to understand the problem,InputN = 5Output61ExplanationThe series is − 5, 13, 25, 41, 61…Solution ApproachA simple approach to solve the problem is by using the general formula for the nth term of the series. The Nth term is given by,Nth term = ( (N*N) + ((N+1)*(N+1)) )Program to illustrate the working of our solution,Example Live Demo#include using namespace std; int calcNthTerm(int N) { return ( ( (N + 1)*( N + 1) ) + (N*N) ) ; } int main() { int N = 7; cout
In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 5, 2, 19, 13, 41, 31, 71, 57…Let’s take an example to understand the problem, InputN = 5Output41ExplanationThe series is − 5, 2, 19, 13, 41, …Solution ApproachA simple approach to solve the problem is by using the general formula for the nth term of the series. The series has different formulas for even and odd values.The Nth term is given by, Nth term = (N-1)^2 + N, if N is even i.e N%2 == 0 Nth term ... Read More
In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 3, 14, 39, 84…Let’s take an example to understand the problem,InputN = 4Output84Explanation4th term − ( (4*4*4) + (4*4) + 4 ) = 64 + 16 + 4 = 84Solution ApproachA simple approach to solve the problem is by using the general formula for the nth term of the series. The formula for,Nth term = ( (N*N*N) + (N*N) + (N))Program to illustrate the working of our solution,Example Live Demo#include using namespace std; int calcNthTerm(int N) { return ( (N*N*N) + (N*N) + (N) ); } int main() { int N = 6; cout
In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 1,8, 54, 384 ...Let’s take an example to understand the problem,InputN = 4Output384Explanation4th term − (4 * 4 * (4!) = 384Solution ApproachA simple approach to solve the problem is by using the general formula for the nth term of the series. The formula for,Nth term = ( N * N * (N !) )Program to illustrate the working of our solution,Example Live Demo#include using namespace std; int calcFact(int N) { int fact = 1; for (int i = 1; i
In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 1,6, 18, 40, 75 ...Let’s take an example to understand the problem,InputN = 4Output40Explanation4th term − (4 * 4 * 5 ) / 2 = 40Solution ApproachA simple approach to solve the problem is by using the general formula for the nth term of the series. The formula for,Nth term = ( N * N * (N + 1) ) / 2Program to illustrate the working of our solution,Example Live Demo#include using namespace std; int calcNthTerm(int N) { return ( (N*N*(N+1))/2 ); } int main() { int N = 5; cout
In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 1,5, 32, 288 ...Let’s take an example to understand the problem,InputN = 4Output288Explanation4th term − (4^4) + (3^3) + (2^2) + (1^1) = 256 + 27 + 4 + 1 = 288Solution ApproachA simple approach to solve the problem is by using the general formula for the nth term of the series. The formula for,Nth term = ( N^N ) + ( (N-1)^(N-1) ) + … + ( 2^2 ) + ( 1^1 )Program to illustrate the working of our solution,Example Live Demo#include using namespace std; int calcNthTerm(int N) { if (N
In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 1,1, 2, 6, 24, ...Let’s take an example to understand the problem,InputN = 7Output720ExplanationThe series is − 1, 1, 2, 6, 24, 120, 720Solution ApproachA simple approach to solve the problem is by using the general formula for the nth term of the series. The formula for,Nth term = (N−1)!Program to illustrate the working of our solution,Example Live Demo#include using namespace std; int calcNthTerm(int N) { if (N
In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 1, 2, 2, 4, 4, 4, 4, 8, 8, 8, 8, 8, 8, 8, 8…Let’s take an example to understand the problem, InputN = 7Output4Solution ApproachA simple approach to solve the problem is using a loop to find the term at the nth position. The terms will be updated by doubling after each iteration. And adding it to the term counter.Program to illustrate the working of our solution, Example#include using namespace std; int calcNthTerm(int N) { ... Read More
An expression is a combination of operators and operands which reduces to a single value. An operation is performed on a data item which is called an operand. An operator indicates an operation to be performed on data.For example, z = 3+2*1z = 5Primary expressions − It is an operand which can be a name, a constant or any parenthesized expression. Example − c = a+ (5*b);Postfix expressions − In a postfix expression, the operator will be after the operand. Example − ab+Prefix expressions − n a prefix expression, the operator is before the operand. Example − +abUnary expression − ... Read More