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ExamplesApproach to solve this problemStep 1 − Define a method that accepts the head of a linked list.Step 2 − If head == nil, return; else, call ReverseLinkedList, recursively.Step 3 − Print head.value at the end.Example Live Demopackage main import "fmt" type Node struct { value int next *Node } func NewNode(value int, next *Node) *Node{ var n Node n.value = value n.next = next return &n } func TraverseLinkedList(head *Node){ fmt.Printf("Input Linked List is: ") temp := head for temp != nil { fmt.Printf("%d ", temp.value) ... Read More
ExamplesApproach to solve this problemStep 1 − Define a method that accepts the head of the linked list.Step 2 − Initialize a variable, count := 0.Step 3 − Iterate the given linked list till it reaches the last node.Step 4 − Increase the count by 1 in the loop.Step 5 − Return count.Example Live Demopackage main import "fmt" type Node struct { value int next *Node } func NewNode(value int, next *Node) *Node{ var n Node n.value = value n.next = next return &n } func CountNodes(head *Node){ fmt.Printf("Input Linked List is: ") ... Read More
ExamplesApproach to solve this problemStep 1 − Let’s define a structure of the node.Step 2 − Make the Linked List such that the previous node would store the address of the next node.Example Live Demopackage main import "fmt" type Node struct { value int next *Node } func NewNode(value int) *Node{ var n Node n.value = value n.next = nil return &n } func TraverseLinkedList(head *Node){ fmt.Printf("Linked List: ") temp := head for temp != nil { fmt.Printf("%d ", temp.value) temp = temp.next } } ... Read More
ExamplesFor example, n = 1 (Binary Representation of 1: 1)For example, n = 5 (Binary Representation of 5: 101)For example, n = 20 (Binary Representation of 5: 10100)For example, n = 31 (Binary Representation of 31: 11111)Approach to solve this problemStep 1 − Define a method that accepts an integer, n.Step 2 − Convert n into binary representation using golang packageStep 3 − Return the converted binary representation.Example Live Demopackage main import ( "fmt" "strconv" ) func IntegerToBinary(n int) string { return strconv.FormatInt(int64(n), 2) } func main(){ n := 1 fmt.Printf("Binary Representation of %d is %s.", ... Read More
ExampleSuppose we have the following binary tree.Preorder Tree Traversal Output: 1, 2, 4, 5, 3, 6, 7.Approach to solve this problemStep 1 − If the root node of the given tree is nil, then return; else, follow the steps given below.Step 2 − Print the root node data.Step 3 − Traverse the Left sub-tree.Step 4 − Traverse the Right sub-tree.Example Live Demopackage main import "fmt" type Node struct { data int left *Node right *Node } func (root *Node)PreOrderTraversal(){ if root !=nil{ fmt.Printf("%d ", root.data) root.left.PreOrderTraversal() root.right.PreOrderTraversal() ... Read More
ExamplesFor example, arr = [1, 4, 5, 1, 4, 5, 1] => Odd-occurring element in the array is: 1Approach to solve this problemStep 1 − Define method that accepts an array.Step 2 − Declare a xor variable, i.e., xor := 0.Step 3 − Iterate input array and perform xor operation with each element of the array.Step 4 − At the end, return xor.Example Live Demopackage main import ( "fmt" ) func FindOddOccurringElement(arr []int) int{ xor := 0 for i := 0; i < len(arr); i++ { xor = xor ^ arr[i] } return ... Read More
ExamplesFor example, n = 12 => 12 is not the power of 4.For example, n = 64 => 64 is the power of 4.Approach to solve this problemStep 1 − Define a method that accepts a number n.Step 2 − Divide log(n) by log(4), store in res.Step 3 − If the floor of res is same as the res, then print that n is the power of 4.Step 4 − Else, print that n is not the power of 4.Example Live Demopackage main import ( "fmt" "math" ) func CheckPowerOf4(n int){ res := math.Log(float64(n)) / math.Log(float64(4)) if ... Read More
ExamplesFor example, n = 12 => Previous number power of 2 is 8.For example, n = 20 => Previous number power of 2 is 16.Approach to solve this problemStep 1 − Define a method that accepts a number n.Step 2 − Perform n | (n >> k), where k is 1, 2, 4, 8, 16.Step 3 − At the end, return n - (n >> 1).Example Live Demopackage main import "fmt" func PreviousPowOf2(n int) int{ n = n | (n >> 1) n = n | (n >> 2) n = n | (n >> 4) n ... Read More
ExamplesFor example, n = 12 => Next number power of 2 is 16.For example, n = 20 => Next number power of 2 is 32.Approach to solve this problemStep 1 − Define method, that accepts a number n.Step 2 − Iterate k := 1 until k < n.Step 3 − In a loop, calculate k
ExamplesFor example, x = 12, y = 15 => Maximum number is 15.For example, x = 13, y = 17 => Minimum number is 13.Approach to solve this problemStep 1 − Define method, findMax and findMin, that accept two integer x and y.Step 2 − Return integer according to defined method.Example Live Demopackage main import "fmt" func FindMax(x, y int){ fmt.Printf("Maximum element in %d, and %d is: %d", x, y, x - ((x - y) & ((x - y) >> 31))) } func FindMin(x, y int) { fmt.Printf("Minimum element in %d, and %d is: %d", x, y, y ... Read More