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Articles on Trending Technologies
Technical articles with clear explanations and examples
HTML DOM Input URL type Property
The HTML DOM Input URL type property returns/sets type of Input URL.SyntaxFollowing is the syntax −Returning string valueinputURLObject.typeSetting type to string valueinputURLObject.type = stringValueString ValuesHere, “stringValue” can be the following −stringValueDetailsemailIt defines that input type is emailurlIt defines that input type is urlradioIt defines that input type is radiotelIt defines that input type is tel and a number keypad is shown for inputExampleLet us see an example for Input URL type property − Input URL type form { width:70%; margin: 0 auto; text-align: center; } * ...
Read MoreCan we to override a catch block in java?
DescriptionWhen a piece of code in particular method throws an exception, and is handled using try-catch pair. If we are calling this method from another one and, the calling line is wrapped within try-catch pair. Now, how can I override the catch block by the catch block of the calling method.When a piece of code in a method throws an exception (compile time) we must either handle it by wrapping it within the try-catch pair or, throw it (postpone) to the calling method using the throws keyword else a compile time error occurs.In the following Java example the code in ...
Read MoreAn interesting method to print reverse of a linked list in C++
A linked list is a data structure that stores data elements in linked form. Each node of the linked list has a data element and a link.Print reverse of a linked list is a common problem that needs to be addressed in problem solving. So, here we will learn an interesting way to print reverse of a linked list in c++ programming language.Generally print a reverse linked list needs modifications in the list or multiple traversing of the list but this method does not require any such things and also traverses the linked list only once.The logic of this method ...
Read MoreCan we throw an Unchecked Exception from a static block in java?
A static block is a block of code with a static keyword. In general, these are used to initialize the static members. JVM executes static blocks before the main method at the time of class loading.Examplepublic class MyClass { static{ System.out.println("Hello this is a static block"); } public static void main(String args[]){ System.out.println("This is main method"); } }OutputHello this is a static block This is main methodExceptions in static blockJust like any other method in Java when an exception occurs in static block you can handle it using try-catch pair.Exampleimport ...
Read MoreC++ program to find two numbers with sum and product both same as N
In this tutorial, we will be discussing a program to find two numbers (say ‘a’ and ‘b’) such that botha+b = N and a*b = N are satisfied.Eliminating ‘a’ from both the equations, we get a quadratic equation in ‘b’ and ‘N’ i.eb2 - bN + N = 0This equation will have two roots which will give us the value of both ‘a’ and ‘b’. Using the determinant method to find the roots, we get the value of ‘a’ and ‘b’ as, $a= (N-\sqrt{N*N-4N)}/2\ b= (N+\sqrt{N*N-4N)}/2 $Example#include //header file for the square root function #include using namespace std; ...
Read MoreCheck horizontal and vertical symmetry in binary matrix in C++
Suppose we have a binary matrix of order M x N. The task is to check whether the matrix is horizontally symmetric, vertically symmetric or both. One matrix is said to be horizontally symmetric if the ith row is the same as the (M – i)th row, this is said to be vertically symmetric if the jth column is the same as the (N – j)th column. Suppose the input matrices are like below −011101011This is Horizontally symmetric.111101111This is Vertically symmetric.111101111This is Horizontally as well as vertically symmetric.We will solve this problem using two phases. At first, we will check ...
Read MoreC++ program to find uncommon characters in two given strings
In this article, we will be discussing a program to find out the uncommon characters during comparison of two different given strings.As we know, strings are nothing but an array of characters. Therefore, for comparison we would be traversing through the characters of one string and simultaneously checking if that element exists in the other string.If we let the first string be A and the second string B.Then it would give us A - B. Similarly we can calculate B - A.Combining both of these results we would get( A - B ) ∪ ( B - A )i.e the ...
Read MoreC++ program to find union and intersection of two unsorted arrays
In this article, we will be discussing a program to find the union and intersection of two given unsorted arrays.Let us denote the two arrays with ‘A’ and ‘B’. Then union of those arrays is denoted by A ∪ B which is basically an array of all the elements in both the given arrays; provided that each element repeats only once.To find this, we will create a separate array and copy down all the elements from the first array. Then we will traverse through the elements of the second array and check if it is already present in the union ...
Read MoreApothem of a n-sided regular polygon in C++
n-sided regular polygon is a closed figure of n sides that has all sides and angles of equal length. The below figure shows a 6 sided regular polygon commonly known as hexagon.Apothem is a line in the polygon that connects the center of the figure to the side. And it is perpendicular to one of its sides that makes it smallest in length.Now, let drive the formula for its length.The angle made by the side of an n sided polygon is 360/n.Now, as in the figure, the angle is equal to (360 / n )/2 = 180 /nNow taking the ...
Read MoreC++ program to find unique pairs such that each element is less than or equal to N
In this article, we will be discussing a program to find unique pairs of numbers having elements less than or equal to N and following some certain conditions −The square of difference between the two numbers must be equal to the LCM of those two numbers.The HCF of those two numbers can be represented as a product of any two consecutive numbers.The best approach to solve this problem would be to take two consecutive numbers (starting from 1) and finding the multiples of product of those numbers. Then among the multiples, to specify to one pair of numbers we need ...
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