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Articles on Trending Technologies
Technical articles with clear explanations and examples
Print a pattern without using any loop in C++
In this problem, we are given a number n. Our task is to print patterns with decreasing to 0 or negative then increasing back to the number.Let’s take an example to understand the problem,Input: n = 12 Output: 12 7 2 -3 2 7 12To solve this problem, we will use recursion and call the function after each update. The track of update is kept using the flag variable which tells the function to increase or decrease the number by 5.ExampleThe below code gives the implementation of our solution,#include using namespace std; void printNextValue(int m){ if (m > 0){ cout
Read MoreMerge Two Binary Trees in C++
Suppose we have two binary trees and consider that when we put one of them to cover the other, some nodes of the two trees are overlapped while the others are overlapping. We have to merge them into a new binary tree. The merge rule is like that if two nodes are overlapping, then sum node values up as the new value of the merged node. Otherwise, the non-empty node will be used as the node of the new tree.So if the trees are −Then the output will be −To solve this, we will follow these steps −The method is ...
Read MoreFind the Diameter or Longest chord of a Circle in C++
Suppose we have radius r is given. We have to find the diameter or longest chord of the circle. If the radius is 9, and diameter will be 18. This task is extremely simple, we have to find the 2*r, that is the diameter of the circle.Example#include using namespace std; int getDiameter(int r) { return 2*r; } int main() { int r = 9; cout
Read MorejQuery Misc param() Method
The param() method in jQuery is used to create a serialized representation of an array or object.SyntaxThe syntax is as follows −$.param(obj, val)Above, obj is the object to serialize, whereas Val specifies whether or not to use the traditional style of param serialization.ExampleLet us now see an example to implement the jQuery param() method− $(document).ready(function(){ ob = new Object(); ob.stdid = "S01"; ob.roll = 3; $("button").click(function(){ $("p").text($.param(ob)); }); }); Student Details Serialized Representation OutputThis will produce the following output−Click on the button to get serialized representation−
Read MoreFind the K-th minimum element from an array concatenated M times in C++
Consider we have an array A, and another two integers K and M. We have to find Kth minimum element after concatenating the array to itself M number of times. Suppose the array is like A = [3, 1, 2], K = 4 and M = 3, so after concatenating A, 3 times, it will be [3, 1, 2, 3, 1, 2, 3, 1, 2], the 4th smallest element is 2 here.To solve this problem, we will sort the array A, then return the value, present at index ((K – 1)/M), of the array.Example#include #include using namespace std; int findKSmallestNumber(int ...
Read MoreMaximum length of a sub-array with ugly numbers in C++
Problem statementGiven an array arr[] of N elements (0 ≤ arr[i] ≤ 1000). The task is to find the maximum length of the sub-array that contains only ugly numbers.Ugly numbers are numbers whose only prime factors are 2, 3 or 5.For Example below are the few number from series: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, …ExampleIf input array is {1, 2, 7, 9, 120, 810, 374} then answer is 3 as −Longest possible sub-array of ugly number sis {9, 120, 810}AlgorithmTake a unordered_set, and insert all the ugly numbers which are less than 1000 in ...
Read MoreTwo City Scheduling in C++
Suppose there are 2N persons. A company wants to organize one interview. The cost for flying the i-th person to city A is costs[i][0], and the cost for flying the i-th person to city B is costs[i][1]. We have to find the minimum cost to fly every person to a city, such that N people arrive in every city. So if the given list is [[10, 20], [30, 200], [400, 50], [30, 20]] The output will be 110. So we will send the person P1 to city A with cost 10, Second person to city A with cost 30, third ...
Read MoreMaximal Disjoint Intervals in C++
DescriptionGiven a set of N intervals, the task is to find the maximal set of mutually disjoint intervals. Two intervals [i, j] & [k, l] are said to be disjoint if they do not have any point in commonIf intervals are {{10, 20} {23, 35}, {15, 21}, {37, 41}} then maximum non-overlapping disjoint pairs are −{10, 20} {23, 35} {37, 41}Note that we cannot include {15, 21} as it will overlap with {10, 20}Algorithm1. Sort the intervals, with respect to their end points. 2. Traverse the all intervals, if we get two overlapping intervals, then choose the interval with lower ...
Read MorePlay with Chips in C++
Suppose there are some chips, the i-th chip is at present at position chips[i]. We can perform any of the two following types of operations any many numbers of times as we want (possibly zero) on any chip −Move the i-th chip by 2 units to the left side or to the right side with a cost of 0.Move the i-th chip by 1 unit to the left side or to the right side with a cost of 1.Initially, there can be two or more chips. We have to return the minimum cost needed to move all the chips to ...
Read MoreMaximize a given unsigned number by swapping bits at its extreme positions in C++
Problem statementGiven a number maximize it by swapping bits at its extreme positions i.e. at first and last position, second and second last position and so on.If the input number is 8 then its binary representation is−00000000 00000000 00000000 00001000After swapping bits at extreme positions number becomes −00010000 00000000 00000000 00000000 and its decimal equivalent is: 268435456Algorithm1. Create a copy of the original number 2. If less significant bit is 1 and more significant bit is 0 then swap the bits in the bit from only, continue the process until less significant bit’s position is less than more significant bit’s ...
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