Article Categories
- All Categories
-
Data Structure
-
Networking
-
RDBMS
-
Operating System
-
Java
-
MS Excel
-
iOS
-
HTML
-
CSS
-
Android
-
Python
-
C Programming
-
C++
-
C#
-
MongoDB
-
MySQL
-
Javascript
-
PHP
-
Economics & Finance
Articles on Trending Technologies
Technical articles with clear explanations and examples
Find elements of an Array which are Odd and Even using STL in C++
Given with an array and the task is to find the number of odd and even elements in an array using standard template library in C++.To solve this problem we are using the function count_if() present in C++ standard template library. What is a count_if() function?Syntaxcount_if(LowerBound, UpperBound, function)Description − This function returns the number of elements in an array that satisfies the given condition. It takes three parameters.Lower Bound − It points to the first element of an array or any other sequence.Upper Bound − It points to the last element of an array or any other sequence.Function − It ...
Read MoreEvaluate Reverse Polish Notation in C++
Suppose we have a triangle. We have to find the minimum path sum from top to the bottom. In each step we can move to adjacent numbers on the row below.For example, if the following triangle is like[ [2], [3, 4], [6, 5, 7], [4, 1, 8, 3] ]The minimum path sum from top to bottom is 11 (2 + 3 + 5 + 1 = 11).Let us see the stepsCreate one table to use in Dynamic programming approach.n := size of trianglefor i := n – 2 down to 0for j := 0 to idp[j] ...
Read MoreConvert a tree to forest of even nodes in C++
In this tutorial, we will be discussing a program to convert a tree to a forest of even nodes.For this we will be provided with a binary tree of say N nodes. Our task is to calculate the maximum number of edges that can be removed to get forest of even nodes.Example#include #define N 12 using namespace std; //returning the number of nodes of subtree //having the root node int depth_search(vector tree[N], int visit[N], int *ans, int node){ int num = 0, temp = 0; //marking nodes as visited visit[node] = 1; for (int i = ...
Read MoreConvert all lowercase characters to uppercase whose ASCII value is co-prime with k in C++
In this tutorial, we will be discussing a program to convert all lowercase characters to uppercase whose ASCII value is co-prime with k.For this we will be provided with a string and an integer value k. Our task is to traverse through the given string and change to uppercase all those characters whose ASCII value is co-prime with the given integer k.Example#include using namespace std; //modifying the given string void convert_string(string s, int k){ int l = s.length(); for (int i = 0; i < l; i++) { int ascii = (int)s[i]; ...
Read MoreGas Station in C++
Suppose there is a circle, and there are n gas stations on the circle. We have two sets of data like −The amount of gas that every gas stations hasDistance from one gas stations to another.Calculate the first point, from where a car will be able to complete the circle. Assume for 1 unit of gas, the car can go 1 unit of distance. Suppose there are four gas stations, and the amount of gas, and distance from the next gas stations is as like [(4, 6), (6, 5), (7, 3), (4, 5)], the first point from where car can ...
Read MoreEvaluate Reverse Polish Notation in C++ Program
Suppose we have Reverse polish notation and we have to evaluate the value. The reverse polish notation is also known as postfix expression. Here we have to use the stack data structure to solve the postfix expressions.From the postfix expression, when some operands are found, pushed them in the stack. When some operator is found, two items are popped from stack and then the operation is performed in the correct sequence. After that, the result is also pushed in the stack for future use. After completing the whole expression, the final result is also stored in the stack top. So ...
Read MoreLetter Case Permutation in C++
Suppose we have a string with letters and numbers. We have to generate all possible combinations of that string by taking uppercase and lowercase versions of letters that are present in the string. So if one string has only numbers, only that will be returned. Suppose the string is like “1ab2”, then the strings will be [“1ab2”, “1Ab2”, “1aB2”, “1AB2”]To solve this problem, we will use recursive approach. It takes the index parameter to start work from that index. It also takes a temp string up to which the result is created. When the index is same as the string ...
Read MorePrint All Distinct Elements of a given integer array in C++
In this problem, we are given an array of integer values. Our task is to print all distinct elements of the array. The output should contain only distinct values.Let’s take an example to understand the problemInput: array = {1, 5, 7, 12, 1, 6, 10, 7, 5} Output: 1 5 7 12 6 10To solve this problem, we will have to check elements of the array for uniqueness. For this, we will use two nested loops, the outer one will take values and the inner one will check the rest of the values with it. If more than one values ...
Read MorejQuery Traversing Siblings
With jQuery, you can easily find siblings of an element using the following methods: next(), nextAll(), prev(), prevAll(), siblings(), etc. Let us see some of them traverse siblings−next() methodThe next() method is used to return the next sibling element of the selected element. Let us see an example−Example div { width:600px; } .demo * { display: block; border: 2px solid orange; color: blue; padding: 10px; margin: 10px; } $(document).ready(function(){ $("h3").next().css({"color": "gray", "border": "3px dashed blue"}); }); parent sibling sibling ...
Read MoreRotate String in Python
Suppose we have two strings, A and B. We will rotate the string A and check whether it matches with B at any position of rotating, if so then return true, otherwise false. For example, if A = 'abcde', and B = 'bcdea' So answer will be true, as A can be converted to B after rotating it.To solve this, we will follow these steps −When both A and B are empty, then return true, when both are of different length then return falseA := concatenate A after Ai := 0, and j := 0while i < length of Aif ...
Read More