A gulab jamun, contains sugar syrup up to about 30% of its volume. Find approximately how much syrup would be found in 45 gulab jamuns, each shaped like a cylinder with two hemispherical ends with length 5 cm and diameter 2.8 cm (see figure).
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Given:
A gulab jamun contains sugar syrup up to about 30% of its volume.
To do:
We have to find how much syrup would be found in 45 gulab jamuns, each shaped like a cylinder with two hemispherical ends with a length 5 cm and a diameter of 2.8 cm
Solution:
The volume of one piece of gulab jamun
$=$ Volume of the cylindrical portion $+$ Volume of two hemispherical ends
Radius of each hemispherical portion $= \frac{2.8}{2}$
$= 1.4\ cm$
Volume of one hemispherical end $=\frac{2}{3} \pi r^{3}$
$=\frac{2}{3} \times \frac{22}{7}(1.4)^{3}$
$=\frac{2}{3} \times \frac{22}{7} \times (1.4)^3$
$=\frac{2 \times 22 \times 2 \times 14 \times 14}{3 \times 10 \times 10 \times 10}$
$=5.74 \mathrm{~cm}^{3}$
Volume of both hemispherical ends $= 2 \times 5.74$
$= 11.48\ cm^3$
Height of the cylindrical portion $=$ Total height $-$ Radius of both hemispherical ends
$= 5-2(1.4)\ cm$
$= 5-2.8$
$= 2.2\ cm$
The radius of the cylindrical portion $= 1.4\ cm$
The volume of the cylindrical portion of gulab jamun $= \pi r^2h$
$= \frac{22}{7} \times (1.4)^2 \times 2.2$
$= 22\times2\times1.4\times2.2$
$= 13.55\ cm^3$
The total volume of one gulab jamun $=$ Volume of the two hemispherical ends $+$ Volume of the cylindrical portion
$= 11.48+ 13.55$
$= 25.03\ cm^3$
The volume of sugar syrup $= 30 \%$ of the volume of gulab jamun
$= \frac{30}{100} \times 25.03$
$= 7.50\ cm^3$
Therefore,
The volume of sugar syrup in 45 gulab jamuns
$= 45 \times$ (volume of sugar syrup in one gulab jamun)
$= 45 \times 7.50$
$= 337.5\ cm^3$
$= 338\ cm^3$
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