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Java program to find the smallest number in an array
To find the smallest element of the given array, first of all, sort the array.
Sorting an array
- Compare the first two elements of the array
- If the first element is greater than the second swap them.
- Then, compare 2nd and 3rd elements if the second element is greater than the 3rd swap them.
- Repeat this till the end of the array.
After sorting an array print the 1st element of the array.
Example
public class SmallestNumberInAnArray {
public static void main(String args[]){
int temp, size;
int array[] = {10, 20, 25, 63, 96, 57};
size = array.length;
for(int i = 0; i<size; i++ ){
for(int j = i+1; j<size; j++){
if(array[i]>array[j]){
temp = array[i];
array[i] = array[j];
array[j] = temp;
}
}
}
System.out.println("Smallest element of the array is:: "+array[0]);
}
}Output
Smallest element of the array is:: 10
Another solution
You can also sort the elements of the given array using the sort method of the java.util.Arrays class then, print the 1st element of the array.
Example
import java.util.Arrays;
public class LargestNumberSample {
public static void main(String args[]){
int array[] = {10, 20, 25, 63, 96, 57};
int size = array.length;
Arrays.sort(array);
System.out.println("sorted Array ::"+Arrays.toString(array));
int res = array[0];
System.out.println("smallest element is ::"+res);
}
}Output
sorted Array ::[10, 20, 25, 57, 63, 96] largest element is ::10
Updated on: 13-Mar-2020
13K+ Views
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