Floating point operators and associativity in Java

Java Programming Java 8 Object Oriented Programming

Following programs shows the float arithmetic can cause dubious result if integer values are used using float variables.

Example

public class Tester {
   public static void main(String[] args) {

      float a = 500000000;
      float b = -500000000;
      float c = 1;
      float sumabc1 = a+(b+c);
      float sumabc2 =(a+b)+c;

      System.out.println("Floating Point Arithmetic");
      System.out.println("a + ( b + c ) : " + sumabc1);
      System.out.println("(a + b) + c : " + sumabc2);

      float sumbc = b + c;
      float sumab = a + b;

      System.out.println("b + c : " + sumbc);
      System.out.println("a + b : " + sumab);

      int a1 = 500000000;
      int b1 = -500000000;
      int c1 = 1;

      int sumabc11 = a1+(b1+c1);
      int sumabc21 =(a1+b1)+c1;

      System.out.println("Integer Arithmetic");
      System.out.println("a + ( b + c ) : " + sumabc11);
      System.out.println("(a + b) + c : " + sumabc21);

      int sumbc1 = b1 + c1;
      int sumab1 = a1 + b1;

      System.out.println("b + c : " + sumbc1);
      System.out.println("a + b : " + sumab1);
   }
}

Output

Floating Point Arithmetic
a + ( b + c ) : 0.0
(a + b) + c : 1.0
b + c : -5.0E8
a + b : 0.0
Integer Arithmetic
a + ( b + c ) : 1
(a + b) + c : 1
b + c : -499999999
a + b : 0

Here you can see that a + ( b + c ) is not same as (a + b) + c in float arithmetic.

The reason behind the same is the rounding off of the result because of floating point arithmetic. b + c results in -500000000 instead of -499999999 whereas the same in integer arithmetic yield the desired result.

Fendadis John

Updated on 21-Jun-2020 14:24:45

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