Volume Calculation - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - What number of blocks will be expected to develop a divider 4 m long, 3 m high and 13 cm expansive , if every block measures 20 cm *12cm*6.5 cm?

A - 500

B - 1000

C - 1500

D - 2000

Answer : B

Explanation

Volume of wall = (400*300*13) cm3
Volume of each bricks = (20*12*6.5) cm3
No. of bricks = (400*300*13 /20*12*13)*2 = 1000

Q 2 - A rectangular water tank is open at the top. Its ability is 24m3. Its length and broadness are 4m and 3m separately. Overlooking the thickness of the material utilized for building the tank, the aggregate expense of painting the internal and external surfaces of the tank at Rs 10 for every m2, is:

A - Rs 400

B - Rs. 500

C - Rs. 600

D - Rs. 800

Answer : D

Explanation

Let the depth of the tank be x meters. Then, 4*3*x = 24 ⇒x =2m
Area of the surface to be painted = 2* [{2*(L+b)*h} + (L*b)}]
= 2*[2*(4+3)*2+ (4*3)] m2= 80m2
Cost of painting = (80*10) = 800 Rs.

Q 3 - A tank is 7m long and 4m wide. At what pace ought to water gone through a channel 5 cm expansive and 4cm profound so that in 6 hours and 18 minutes, water level in the tank ascends by 4.5m?

A - 12 km/hr

B - 10 km/hr

C - 14 km/hr

D - none of these

Answer : B

Explanation

Volume of water flown = (7*4*9/2) m3=126 m3
Let the speed of the water be x km/hr.
(x*1000*63/10)*5/100*4/100= 126 ⇒ 63x/5=126
⇒x = (5*126)/63= 10
∴ Speed of water = 10 km/hr

Q 4 - A room is 10 m long, 8m wide and 3.3 m high. What number of men can be obliged in this room if every man requires 3m3 of space?

A - 99

B - 88

C - 77

D - 75

Answer : B

Explanation

Volume of the room = (10*8*3.3) m3= 264m3
Volume required by 1man = 3m3
Required number of men = 264/3 = 88

Q 5 - The diagonal of a 3D shape (cube) measures 4√3 cm. Its volume is:

A - 8 cm3

B - 16 cm3

C - 27 cm3

D - 64 cm3

Answer : D

Explanation

√3a= 4√3 ⇒ a= 4
Volume = a3= (4*4*4) cm3= 64cm3

Q 6 - The rate increment in the surface zone of a 3D square (cube) when every side is multiplied is:

A - 150%

B - 200%

C - 300%

D - 600%

Answer : C

Explanation

Let each side be a, Then its surface area =6a2
New side =2a, new surface area = 6(2a) 2=24a2
Increase % = (18a2/6a2*100) %= 300%

Q 7 - If every side of a 3D square of volume v is multiplied, its volume gets to be ℏv where ℏ is equivalent to:

A - 2

B - 4

C - 8

D - 16

Answer : C

Explanation

Let each side be a, then, V= a3
New volume = (2a) 3= 8a3= 8V
∴ℏV= 8V⇒ℏ= 8

Q 8 - A round and hollow has a width of 14cm and the territory of its bended surface is 220 sq. cm. The volume of the chamber is:

A - 770 cm3

B - 1000 cm3

C - 1540 cm3

D - 6622 cm3

Answer : A

Explanation

r = 7cm and 2 πrh  = 220 ⇒2*22/7*7*h = 220 ⇒h = 5 cm
Volume = πr2h (22/7*7*7*5) = 770 cm3

Q 9 - 0.88 m3. Of iron is softened and shaped as iron poles, each of distance across 2cm and length 7 m. What number of bars is shaped?

A - 400

B - 392

C - 616

D - 2000

Answer : A

Explanation

For each iron rod, r = 1 cm = 1/100 m and h= 7m
Volume of 1 iron rod = πr2h = (22/7* 1/100 *1/100 *7) m3
= 11/5000 m3
No. of iron rods= (88/100* 5000/11) = 400

Q 10 - If 1 cubic cm of cast iron weight 21 gms. At that point the heaviness of a cast iron funnel of lenght1 m with a drag of 3 cm and in which the thickness of the metal is 1cm, is:

A - 21 kg

B - 24.2 kg

C - 18.6 kg

D - 26.4 kg

Answer : D

Explanation

External radius = 2.5cm, length= 100cm
External volume = [π*(2.5)2*100] cm3
Internal radius = 1.5 cm
Internal volume = [π*(1.5)2*100] cm3
Volume of metal =[π*(2.5)2*100-π*(1.5)2*100] cm3
=π*100*{(2.5)2-(1.5)2} = (22/7*100*4*1) cm3
Weight of metal = (8800/7 -21/1000) kg = 26.4 kg

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