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Area Calculation - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Area Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The length of a rectangular plot is 9/2 times that of its broadness. On the off chance that the region of the plot is 200 square meters, then what is the length?
Answer : D
Explanation
Let the breadth be x meters. Then, length =9x/2 meters. ∴ X*9x/2= 200 ⇒x2= 400/9 ⇒x= 20/3 ∴ Length = (9/2*20/3) m = 30m
Q 2 - A rectangular field has measurement 25m by 15m .Two commonly opposite entries of 2m width have been left in its focal Part and grass has been developed in whatever is left of the field. The territory under the grass is:
Answer : B
Explanation
Area under the grass =[(25*15)-{(25*2)+(15*2)-(2*2)}]
= {375-(50+30-40} m2 = (375-76) m2 = 299 m2
Q 3 - If the proportion of the ranges of two squares is 9:1, then the proportion of their edge is:
Answer : B
Explanation
Let their area be 9x2 and x2 sq. units. Then, their sides are respectively 3x units and x units. ∴ Their Perimeter are (4*3 x) and 4x units. Required ratio = 12x: 4x= 3:1
Q 4 - Of the two square fields, the range of the one is 1 hectare, while another is more extensive by 1%. The distinction in ranges is:
Answer : B
Explanation
Area of one Sq. field= 10000m2 Side of this field = √10000m =100m Side of another square = 101 m Difference of area = [(101) 2-(100) 2] m2 =(101+100)(101-100)m2 = (201*1)m2= 201m2
Q 5 - A circular wire of radius 42 cm is cut and bent in the form of a rectangle whose side are in the ratio of 6:5. The smaller side of the rectangle is:
Answer : B
Explanation
Length of the wire = circumference of the circle with r=42cm = (2* 22/7 *42) cm = 264 cm Let the length of the rectangle be 6x cm. then, its breadth=5x cm ∴ 2 (6x+5x) = 264 ⇒11x= 132 ⇒ x= 12. Smaller side of the rectangle= (5*12) cm = 60 cm
Q 6 - If an area enclosed by a circle or a square or an equilateral triangle is the same, then the maximum perimeter is possessed by:
Answer : A
Explanation
πR2 = s2= √3/4 a2 =A ⇒ R= √ (A/π), s =√A and a =√4A/ (√3) Perimeter of circle = 2πR= 2π√ (A/π) =2√A*√π= 2*√3.14*√A= (2*1.77*√A) = (3.54* √A) Perimeter of square = 4√A Perimeter of triangle = 3a = 3√ (4A/√3= 6/3 (ki power1/4). √A =3 (ki power3/4).2√A = (27)⅟4 .2√A>4√A ∴ Perimeter of triangle is maximum.
Q 7 - Every side of a square is equivalent to every side of an equilateral triangle. The proportion of their ranges is:
Answer : D
Explanation
Let, side of square = side of equilateral triangle = x Ratio of their areas = x2: √3x2/4 = 4:√3
Q 8 - The length of every side of an equilateral triangle is 24 cm. The region of its engraved circle is:
Answer : D
Explanation
Let the height of the triangle be h then, 1/2 * 24*h = √3/4 *24*24 ⇒h= 12 √3 ∴ 3r = 12 √3 ⇒r = 4√3 Area of in circle = π* (4√3)2 = 48πcm2
Q 9 - Each side of an equilateral triangle is equivalent to the span of a circle whose region is 154 cm2. The range of the equilateral triangle is:
Answer : B
Explanation
Let each side of the equilateral triangle be a cm and radius of the circle is r cm. Then , a =r πr2 =154 ⇒22/7 *r2=154⇒ r 2= (154*7/22) = 49 ⇒r= 7 ∴ a = 7cm ⇒ area of ∆ = √ 3/4 *(7)2 cm2=49√3/4 cm2
Q 10 - What is the region of the shaded bit if every side of the square measures 21cm?
Answer : C
Explanation
Area of the shaded region= [(21)2-22/7* (21/2)2] = (441- 693/2) cm2 = (441- 346.5) cm2 = 94.5 cm2
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