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Aptitude - Pipes & Cisterns Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Pipes & Cisterns. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - A tap can fill storage in 8 hours and another tap can discharge it in 16 hours. In the event that both the taps are open, the time taken to fill the tank will be:

Answer : C

Explanation

Net part filled in 1 hr = (1/8 ? 1/16)= 1/16
Total time taken to fill the tank = 16 hrs.

Q 2 - A tank can be filled by a tap in 20 minutes and by another tap in an hour. Both the taps are kept open for 10 minutes and after that the first tap is shutoff. After this, the tank will be totally filled in:

Answer : D

Explanation

Part of the tank filled by both in 10 min. = 10*(1/20+1/60)= 40/60 = 2/3
Remaining part = (1-2/3) = 1/3
1/60 part is now filled in 1 min.
1/3 part is now filled in (60*1/3) min. = 20 min.

Q 3 - Pipes A and B can fill a tank in 20 hours and 30 hours separately and channel C can purge the full tank in 40 hours. In the event that every one of the funnels is opened together, what amount of the reality of the situation will become obvious eventually expected to make the tank full?

Answer : C

Explanation

Net part filled in 1 hr = (1/20+ 1/30 ? 1/40)= 7/120
Time needed to make the tank full = 120/7 hrs.

Q 4 - Two funnels can fill a reservoir in 14hrs and 16 hrs. individually. The funnels are opened all the while and it is found that because of spillage in the last, 32 minutes additional are taken for the reservoir to be topped off. In the event that the storage is full, in what time would the release unfilled it?

Answer : D

Explanation

Work done by two pipes in 1 hr= (1/14+1/16)= 15/112
Total time taken by two pipes and leak in 1 hr= (112/15+32/60) hrs= 8 hrs.
Work done by the leak in 1 hr = (15/112- 1/8) = 1/112
Hence, the leak will empty the full cistern in 112 hrs.

Q 5 - A tank is fitted with two taps A and B. A can fill the tank totally in 45 minutes and B can purge the full tank in 60 minutes. On the off chance that both the taps are opened on the other hand for 1 minute, then in what amount of time the unfilled tank will be filled totally?

Answer : D

Explanation

Work done by A in 1st minutes and B 2nd minute= (1/45- 1/60)= 1/180
Part filled in 2 min = 1/180
Part filled in 358 min = (1/360*358) =   358/360 = 179/180
Remaining part = (1-179/180) = 1/180
1/45 part is filled by A in (45*1/180) min= 1/4 min.
Total time taken to fill it = 358 1/4 min = 5 hrs.58 min 15 sec.

Q 6 - A substantial tanker can be filled by two pipes A and B in an hour and 40 minutes separately. How long will it take to fill the tanker from unfilled state if B is utilized for a fraction of the time and A and B fill it together for the other half?

Answer : D

Explanation

Let the total time taken be x minute. Then,
(1/40*x/2) + (1/60+ 1/40) x/2= 1 ⇒ x/80 + x/48 = 1
⇒3x+ 5x= 240 ⇒8x= 240 ⇒x= 30
Hence, the required time is 30 minutes.

Q 7 - A storage has a hole which would exhaust it in 8 hours. A tap is transformed on which concedes 6 liters a moment into the reservoir and it is currently purged in 12 hours. What number of liters does the reservoir hold?

Answer : D

Explanation

Part filled in 1 hour = (1/8- 1/12)= 1/24
Time taken to fill the cistern= 24 hours
Water moved in it 24 hours = (6*60*24) = 8640 liters.
Capacity of the cistern = 8640 liters.

Q 8 - A cistern has 3 pipes A, B and C. A and B can ill it in 3 hours and 4 hours respectively while C can empty the completely filled cistern in 1 hour. If the pipes are opened in order at 3, 4 and 5 pm respectively, at what time will the cistern be empty?

Answer : A

Explanation

In 2 hours Pipe A will fill = 2/3 tank
In 1 hour Pipe B will fill = 1/4 tank
Part of tank filled till 5 PM = (2/3) + (1/4)
= 11/12

Remaining part = 1 - (11/12)
= 1/12

Net part emptied when A, b and C are opened = (1/3) +( 1/4) - 1
= (4+3-12)/12
=  -5/12
∴ 5/12 part is emptied in 1 hour.
∴ 11/12 is emptied in (12/5)*(11/12) = 11/5
= 2 hr 12 min
∴ Tank will be emptied at 7:12 PM.

Q 9 - A pump can fill a tank with water in 2 hours. Because of a leak in the tank, it takes 7/3 hours to fill the tank. The leak can empty the filled tank in?

Answer : D

Explanation

Part of the tank filled by the pump in 1 hour = 1/2
Part of the tank filled by the pump in 1 hour because of the leak = 3/7
∴ Part of the tank emptied by the leak in 1 hour = 1/2 - 3/7
= 1/14
∴ Leak will empty the tank in 14 hours.

Q 10 - Two pipes can fill a tank in 12 hours and 15 hours respectively. A third pipe can empty it in 20 hours. If the tank is empty and all the three pipes are opened, then the tank will be full in (in hour) ?

Answer : C

Explanation

Part of tank filled by both the pipes in 1 hour = 1/12 + 1/15
= 3/20
Part of tank emptied by third pipe in 1 hour = 1/20
∴ Part of tank filled when all the pipes are opened simultaneously = 3/20 - 1/20
= 2/20
= 1/10
∴ Tank will be filled in 10 hours.

aptitude_pipes_cisterns.htm