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Write a program in Python to select any random odd index rows in a given DataFrame
Assume, you have a dataframe,
DataFrame is: id mark age 0 1 70 12 1 2 60 13 2 3 40 12 3 4 50 13 4 5 80 12 5 6 90 13 6 7 60 12
And, the result for selecting any random odd index row is,
Random odd index row is: id 4 mark 50 age 13
Solution
To solve this, we will follow the steps given below −
Define a dataframe
Create an empty list to append odd index values
Create a for loop to access all the index. It is defined below,
for i in df.index.values:
Create an if condition to check the odd index. If it is matches, then append the values to the list,
if(i%2==1): l.append(i)
Generate any one random value from the list and store it random_index
random_index = rand.choice(l)
Finally, print the odd index row using the iloc.
df.iloc[random_index]
Example
Let’s see the below implementation to get a better understanding −
import pandas as pd
import random as rand
df = pd.DataFrame({'id': [1,2,3,4,5,6,7],
'mark': [70,60,40,50,80,90,60],
'age':[12,13,12,13,12,13,12]
})
print("DataFrame is:\n",df)
l = []
for i in df.index.values:
if(i%2==1):
l.append(i)
random_index = rand.choice(l)
print("Random odd index row is: \n", df.iloc[random_index])Output
DataFrame is: id mark age 0 1 70 12 1 2 60 13 2 3 40 12 3 4 50 13 4 5 80 12 5 6 90 13 6 7 60 12 Random odd index row is: id 4 mark 50 age 13 Name: 3, dtype: int64
Updated on: 24-Feb-2021
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