# Write a C program to find out the largest and smallest number in a series

## Problem

Let the user enter four series of integers in the console, find out a number which is smallest and largest in a series

## Solution

To calculate the small and large number, we use if conditions. The logic we use to find the largest and smallest number is −

if(minno>q) //checking 1st and 2nd number
minno=q;
else if(maxno&l;q)
maxno=q;
if(minno>r) //checking 1st and 3rd number
minno=r;

## Program 1

Live Demo

#include<stdio.h>
int main(){
int minno,maxno,p,q,r,s;
printf("enter any four numbers:");
scanf("%d%d%d%d",&p,&q,&r,&s);
minno=p;
maxno=p;
if(minno>q) //checking 1st and 2nd number
minno=q;
else if(maxno<q)
maxno=q;
if(minno>r) //checking 1st and 3rd number
minno=r;
else if(maxno<r)
maxno=r;
if(minno>s) //checking 1st and 4th number
minno=s;
else if(maxno<s)
maxno=s;
printf("Largest number from the given 4 numbers is:%d",maxno);
printf("Smallest numbers from the given 4 numbers is:%d",minno);
return 0;
}

## Output

enter any four numbers:34 78 23 12
Largest number from the given 4 numbers is:78
Smallest numbers from the given 4 numbers is:12

## Program 2

The below program finds the smallest and largest element in an array −

#include<stdio.h>
int main(){
int a,i,num,large,small;
printf("Enter the number of elements :");
scanf("%d",&num);
printf("Input the array elements :");
for(i=0;i<num;++i)
scanf("%d",&a[i]);
large=small=a;
for(i=1;i<num;++i){
if(a[i]>large)
large=a[i];
if(a[i]<small)
small=a[i];
}
printf("small= %d",small);
printf("large= %d",large);
return 0;
}

## Output

Enter the number of elements :8
Input the array elements :
1
2
6
4
8
9
3
9
small= 1
large= 9