Write a C program to find out the largest and smallest number in a series

Problem

Let the user enter four series of integers in the console, find out a number which is smallest and largest in a series

Solution

To calculate the small and large number, we use if conditions. The logic we use to find the largest and smallest number is −

if(minno>q) //checking 1st and 2nd number
   minno=q;
else if(maxno&l;q)
   maxno=q;
if(minno>r) //checking 1st and 3rd number
   minno=r;

Program 1

 Live Demo

#include<stdio.h>
int main(){
   int minno,maxno,p,q,r,s;
   printf("enter any four numbers:");
   scanf("%d%d%d%d",&p,&q,&r,&s);
   minno=p;
   maxno=p;
   if(minno>q) //checking 1st and 2nd number
      minno=q;
   else if(maxno<q)
      maxno=q;
   if(minno>r) //checking 1st and 3rd number
      minno=r;
   else if(maxno<r)
      maxno=r;
   if(minno>s) //checking 1st and 4th number
      minno=s;
   else if(maxno<s)
      maxno=s;
   printf("Largest number from the given 4 numbers is:%d
",maxno);
   printf("Smallest numbers from the given 4 numbers is:%d",minno);
   return 0;
}

Output

enter any four numbers:34 78 23 12
Largest number from the given 4 numbers is:78
Smallest numbers from the given 4 numbers is:12

Program 2

The below program finds the smallest and largest element in an array −

#include<stdio.h>
int main(){
   int a[50],i,num,large,small;
   printf("Enter the number of elements :");
   scanf("%d",&num);
   printf("Input the array elements :
");
   for(i=0;i<num;++i)
      scanf("%d",&a[i]);
   large=small=a[0];
   for(i=1;i<num;++i){
      if(a[i]>large)
         large=a[i];
      if(a[i]<small)
         small=a[i];
   }
   printf("small= %d
",small);
   printf("large= %d
",large);
   return 0;
}

Output

Enter the number of elements :8
Input the array elements :
1
2
6
4
8
9
3
9
small= 1
large= 9