Sum of individual even and odd digits in a string number using JavaScript

Problem

We are required to write a JavaScript function that takes in string containing digits and our function should return true if the sum of even digits is greater than that of odd digits, false otherwise.

Example

Following is the code −

 Live Demo

const num = '645457345';
const isEvenGreater = (str = '') => {
   let evenSum = 0;
   let oddSum = 0;
   for(let i = 0; i < str.length; i++){
      const el = +str[i];
      if(el % 2 === 0){
         evenSum += el;
      }else{
         oddSum += el;
      };
   };
   return evenSum > oddSum;
};
console.log(isEvenGreater(num));

Output

false

AmitDiwan

Published on 19-Apr-2021 11:23:27

• Related Questions & Answers
• Find the sum of digits of a number at even and odd places in C++
• Count odd and even digits in a number in PL/SQL
• Difference between sums of odd and even digits.
• Number Split into individual digits in JavaScript
• Number of even substrings in a string of digits in C++
• How to split JavaScript Number into individual digits?
• Count of N-digit Numbers having Sum of even and odd positioned digits divisible by given numbers - JavaScript
• Prime digits sum of a number in JavaScript
• Check if product of digits of a number at even and odd places is equal in Python
• Python program to find the sum of all even and odd digits of an integer list
• Determining sum of array as even or odd in JavaScript
• Separate odd and even in JavaScript
• Fetch Numbers with Even Number of Digits JavaScript
• Splitting number to contain continuous odd or even number using JavaScript
• Difference between product and sum of digits of a number in JavaScript