# Check if product of digits of a number at even and odd places is equal in Python

PythonServer Side ProgrammingProgramming

Suppose we have a number n. We have to check whether the product of odd placed digits and the even placed digits are same or not.

So, if the input is like n = 2364, then the output will be True as product of odd placed numbers are 2 * 6 = 12 and product of even placed numbers are 3 * 4 = 12 which are same.

To solve this, we will follow these steps −

• if num < 10, then
• return False
• odd_place := 1, even_place := 1
• while num > 0, do
• d := last digit of num
• odd_place := odd_place * d
• num := quotient of (num/10)
• if num is same as 0, then
• break
• d := last digit of num
• even_place := even_place * d
• num := quotient of (num/10)
• if odd_place is same as even_place, then
• return True
• return False

## Example

Let us see the following implementation to get better understanding −

Live Demo

def solve(num):
if num < 10:
return False
odd_place = 1
even_place = 1
while num > 0:
d = num % 10
odd_place *= d
num = num//10
if num == 0:
break
d = num % 10
even_place *= d
num = num//10
if odd_place == even_place:
return True
return False
num = 2364
print(solve(num))

## Input

2364

## Output

True