SortedDictionary.Count Property in C#

The SortedDictionary.Count property in C# is used to get the number of key/value pairs contained in the SortedDictionary<TKey, TValue>.

Syntax

The syntax is as follows −

public int Count { get; }

Example

Let us now see an example −

 Live Demo

using System;
using System.Collections;
using System.Collections.Generic;
public class Demo {
   public static void Main(){
      SortedDictionary<int, string> sortedDict = new SortedDictionary<int, string>();
      sortedDict.Add(100, "Mobile");
      sortedDict.Add(200, "Laptop");
      sortedDict.Add(300, "Desktop");
      sortedDict.Add(400, "Speakers");
      sortedDict.Add(500, "Headphone");
      sortedDict.Add(600, "Earphone");
      Console.WriteLine("SortedDictionary key-value pairs...");
      IDictionaryEnumerator demoEnum = sortedDict.GetEnumerator();
      while (demoEnum.MoveNext())
      Console.WriteLine("Key = " + demoEnum.Key + ", Value = " + demoEnum.Value);
      Console.WriteLine("Count of SortedDictionary key-value pairs = "+sortedDict.Count);
      Console.WriteLine("
The SortedDictionary has the key 200? = "+sortedDict.ContainsKey(200));
      sortedDict.Clear();
      Console.WriteLine("Count of SortedDictionary key-value pairs = "+sortedDict.Count);
   }
}

Output

This will produce the following output −

SortedDictionary key-value pairs...
Key = 100, Value = Mobile
Key = 200, Value = Laptop
Key = 300, Value = Desktop
Key = 400, Value = Speakers
Key = 500, Value = Headphone
Key = 600, Value = Earphone
Count of SortedDictionary key-value pairs = 6
The SortedDictionary has the key 200? = True
Count of SortedDictionary key-value pairs = 0

Example

Let us now see another example −

 Live De mo

using System;
using System.Collections;
using System.Collections.Generic;
public class Demo {
   public static void Main(){
      SortedDictionary<int, string> sortedDict = new SortedDictionary<int, string>();
      sortedDict.Add(100, "Inspiron");
      sortedDict.Add(200, "Alienware");
      sortedDict.Add(300, "Projectors");
      sortedDict.Add(400, "XPS");
      Console.WriteLine("SortedDictionary key-value pairs...");
      IDictionaryEnumerator demoEnum = sortedDict.GetEnumerator();
      while (demoEnum.MoveNext())
      Console.WriteLine("Key = " + demoEnum.Key + ", Value = " + demoEnum.Value);
      Console.WriteLine("Count of SortedDictionary key-value pairs = "+sortedDict.Count);
      sortedDict.Add(800, "Notebook");
      sortedDict.Add(10000, "Bluetooth Speaker");
      Console.WriteLine("
SortedDictionary key-value pairs...UPDATED");
      demoEnum = sortedDict.GetEnumerator();
      while (demoEnum.MoveNext())
      Console.WriteLine("Key = " + demoEnum.Key + ", Value = " + demoEnum.Value);
      Console.WriteLine("Count of SortedDictionary key-value pairs (UPDATED) = "+sortedDict.Count);
      sortedDict.Clear();
      Console.WriteLine("
Count of SortedDictionary key-value pairs (UPDATED) = "+sortedDict.Count);
   }
}

Output

This will produce the following output −

SortedDictionary key-value pairs...
Key = 100, Value = Inspiron
Key = 200, Value = Alienware
Key = 300, Value = Projectors
Key = 400, Value = XPS
Count of SortedDictionary key-value pairs = 4
SortedDictionary key-value pairs...UPDATED
Key = 100, Value = Inspiron
Key = 200, Value = Alienware
Key = 300, Value = Projectors
Key = 400, Value = XPS
Key = 800, Value = Notebook
Key = 10000, Value = Bluetooth Speaker
Count of SortedDictionary key-value pairs (UPDATED) = 6
Count of SortedDictionary key-value pairs (UPDATED) = 0