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Set Decimal Place of a Big Decimal Value in Java
We have the following BigDecimal value −
BigDecimal val1 = new BigDecimal("37578975587.876876989");
We have set the decimal place to be −
int decPlaces1 = 3;
Now, we will use the ROUND_DOWN field to set the rounding mode to round towards zero −
// ROUND_DOWN val1 = val1.setScale(decPlaces1, BigDecimal.ROUND_DOWN); String str1 = val1.toString(); System.out.println("Result = "+str1);
To set decimal place of a BigDecimal value in Java, try the following code −
Example
import java.math.BigDecimal; public class Demo { public static void main(String[] argv) throws Exception { int decPlaces1 = 3; int decPlaces2 = 5; BigDecimal val1 = new BigDecimal("37578975587.876876989"); BigDecimal val2 = new BigDecimal("62567875598.976876569"); System.out.println("Value 1 : "+val1); System.out.println("Value 2 : "+val2); // ROUND_DOWN val1 = val1.setScale(decPlaces1, BigDecimal.ROUND_DOWN); String str1 = val1.toString(); System.out.println("Result = "+str1); // ROUND_UP val2 = val2.setScale(decPlaces2, BigDecimal.ROUND_UP); String str2 = val2.toString(); System.out.println("Result = "+str2); } }
Output
Value 1 : 37578975587.876876989 Value 2 : 62567875598.976876569 Result = 37578975587.876 Result = 62567875598.97688
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