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Scraping and Finding Ordered Word in a Dictionary in Python
For solving this problem we need requests module.
For installing requests module,we need this command to get executed at command line.
pip install requests
Scraping
- Import requests module.
- Then we need to fetch data from URL.
- Using UTF-8 decode the text.
- Then convert string into a list of words.
Ordered Finding
- Traverse the list of words using loop.
- Then compare the ASCII value of adjacent character of each word.
- If the comparison is true then print ordered word otherwise store the unordered word.
Example code
import requests
def Words_find():
my_url = ""#put thisurl of .txt files in any website
my_fetchData = requests.get(my_url)
my_wordList = my_fetchData.content
my_wordList = my_wordList.decode("utf-8").split()
return my_wordList
def wordordered():
collection = Words_find()
collection = collection[16:]
my_word = ''
for my_word in collection:
result = 'ordered'
i = 0
l = len(my_word) - 1
if (len(my_word) < 3):
continue
while i < l:
if (ord(my_word[i]) > ord(my_word[i+1])):
result = 'not ordered'
break
else:
i += 1
if (result == 'ordered'):
print(my_word,': ',result)
if __name__ == '__main__':
wordordered()
Updated on: 26-Jun-2020
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