Removing the node at the start of the LinkedList in C#

CsharpServer Side ProgrammingProgramming

To remove the node at the start of the LinkedList, the code is as follows −

Example

 Live Demo

using System;
using System.Collections.Generic;
public class Demo {
   public static void Main(){
      LinkedList<string> list = new LinkedList<string>();
      list.AddLast("One");
      list.AddLast("Two");
      list.AddLast("Three");
      list.AddLast("Three");
      list.AddLast("Three");
      list.AddLast("Four");
      Console.WriteLine("Count of nodes = " + list.Count);
      Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)");
      LinkedList<string>.Enumerator demoEnum = list.GetEnumerator();
      while (demoEnum.MoveNext()) {
         string res = demoEnum.Current;
         Console.WriteLine(res);
      }
      list.RemoveFirst();
      Console.WriteLine("Count of nodes (UPDATED) = " + list.Count);
      Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED");
      demoEnum = list.GetEnumerator();
      while (demoEnum.MoveNext()) {
         string res = demoEnum.Current;
         Console.WriteLine(res);
      }
   }
}

Output

This will produce the following output −

Count of nodes = 6
Elements in LinkedList... (Enumerator iterating through LinkedList)
One
Two
Three
Three
Three
Four
Count of nodes (UPDATED) = 5
Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED Two
Three
Three
Three
Four

Example

Let us see another example −

 Live Demo

using System;
using System.Collections.Generic;
public class Demo {
   public static void Main(){
      LinkedList<string> list = new LinkedList<string>();
      list.AddLast("One");
      list.AddLast("Two");
      list.AddLast("Three");
      list.AddLast("Three");
      list.AddLast("Three");
      list.AddLast("Four");
      Console.WriteLine("Count of nodes = " + list.Count);
      Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)");
      LinkedList<string>.Enumerator demoEnum = list.GetEnumerator();
      while (demoEnum.MoveNext()) {
         string res = demoEnum.Current;
         Console.WriteLine(res);
      }
      list.RemoveFirst();
      Console.WriteLine("Count of nodes (UPDATED) = " + list.Count);
      Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED");
      demoEnum = list.GetEnumerator();
      while (demoEnum.MoveNext()) {
         string res = demoEnum.Current;
         Console.WriteLine(res);
      }
      list.RemoveFirst();
      Console.WriteLine("Count of nodes (UPDATED AGAIN) = " + list.Count);
      Console.WriteLine("Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED AGAIN");
      demoEnum = list.GetEnumerator();
      while (demoEnum.MoveNext()) {
         string res = demoEnum.Current;
         Console.WriteLine(res);
      }
   }
}

Output

This will produce the following output −

Count of nodes = 6
Elements in LinkedList... (Enumerator iterating through LinkedList)
One
Two
Three
Three
Three
Four
Count of nodes (UPDATED) = 5
Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED
Two
Three
Three
Three
Four
Count of nodes (UPDATED AGAIN) = 4 Elements in LinkedList... (Enumerator iterating through LinkedList)..UPDATED AGAIN
Three
Three
Three
Four
raja
Published on 06-Dec-2019 05:48:24
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